Atomic binding in metals: The attraction between the nucleus and the valence electron of a copper atom is best described as which of the following?
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Azero
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Bweak
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Cstrong
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Deither zero or strong
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Evariable but generally zero
Answer
Correct Answer: weak
Explanation
Introduction / Context:In metallic solids such as copper, valence electrons are delocalized and participate in metallic bonding, forming an electron sea. The individual attraction between a given nucleus and a valence electron is therefore weaker than in covalent or ionic bonds where electrons are localized between specific atoms or ions.
Given Data / Assumptions:
- Copper has a single s-type valence electron beyond a filled d-shell.
- In the solid, this electron is delocalized across the lattice.
- We refer to effective binding of valence electrons in metals.
Concept / Approach:
Delocalization causes conduction electrons to respond readily to applied fields and thermal energy, evidenced by good electrical and thermal conductivity. A strong nucleus–valence electron attraction would impede conduction. Zero attraction is unphysical; electrostatic forces always exist, but in the collective metallic environment the effective binding is weak compared to localized bonding scenarios.
Step-by-Step Solution:
Recognize metallic bonding: electrons not tightly bound to individual nuclei.Weak effective attraction facilitates conduction and low ionization for conduction bands.Select “weak.”Verification / Alternative check:
Band theory shows partially filled bands in copper; the small effective mass and high mobility align with weak localization of valence electrons.
Why Other Options Are Wrong:
- Zero: Contradicts Coulomb interaction; cannot be exactly zero.
- Strong: Inconsistent with metallic conduction behavior.
- Either zero or strong/variable-zero: Not a physically meaningful description.
Common Pitfalls:
- Equating core electron binding (strong) with valence electron binding (much weaker in metals).
Final Answer:
weak