Difficulty: Easy
Correct Answer: resistivity of silicon will be higher than that of germanium
Explanation:
Introduction / Context:
Resistivity ρ of a doped semiconductor depends on free carrier concentration and mobility: ρ = 1 / (q (n μ_n + p μ_p)). For the same dopant density, the majority carrier concentration is similar in magnitude, so material-dependent mobility and intrinsic properties determine relative resistivity at room temperature.
Given Data / Assumptions:
Concept / Approach:
Because Ge typically exhibits higher carrier mobility than Si, the conductivity σ = q n μ (for dominant carrier type) is greater in Ge at the same carrier concentration. Therefore, resistivity ρ = 1/σ is lower in Ge and correspondingly higher in Si.
Step-by-Step Solution:
Verification / Alternative check:
Empirical mobility data: μ_n and μ_p in Ge are larger than in Si at 300 K, matching observed lower resistivity in Ge for equal doping levels.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
resistivity of silicon will be higher than that of germanium
Discussion & Comments