Which expression represents a conventional double-sideband AM signal (with carrier present) using m(t) = 2 cos(2π f_m t) and carrier x_c(t) = A_c cos(2π f_c t), without exceeding 100% modulation?

Difficulty: Easy

Correct Answer: x(t) = A_c [1 + m(t)] cos(2π f_c t)

Explanation:


Introduction / Context:
Conventional AM (double sideband with carrier) multiplies a carrier by a DC-plus-message term. Recognizing the correct mathematical form is foundational for understanding spectra, envelope detection, and constraints such as overmodulation (|μ| ≤ 1).


Given Data / Assumptions:

  • Message m(t) = 2 cos(2π f_m t).
  • Carrier x_c(t) = A_c cos(2π f_c t).
  • Conventional AM form: x(t) = A_c[1 + μ cos(2π f_m t)] cos(2π f_c t). Here μ is the modulation index and must satisfy |μ| ≤ 1 to avoid overmodulation.


Concept / Approach:
The presence of a nonzero DC term ensures the envelope never crosses zero when |μ| ≤ 1, enabling simple diode envelope detection. Expressions without the DC term correspond to DSB-SC. Quadrature combinations correspond to phase or frequency translation, not standard AM with carrier.


Step-by-Step Solution:

Identify conventional AM: a carrier scaled by [1 + message term].Match with options: only option (b) has a carrier multiplied by [1 + m(t)].Note about modulation index: with m(t) = 2 cos(⋯), the implicit μ would be 2, which exceeds 1. In practice, one would scale m(t) to keep |μ| ≤ 1. The form, however, is uniquely correct for conventional AM with carrier.


Verification / Alternative check:

Expanding x(t) = A_c cos(2π f_c t) + A_c m(t) cos(2π f_c t) produces a carrier term at f_c and symmetric sidebands at f_c ± f_m—exactly the spectrum of standard DSB-AM with carrier.


Why Other Options Are Wrong:

(a) A_c m(t) cos(2π f_c t) is DSB suppressed-carrier; no DC term (no carrier).(c) Uses the identity cosα cosβ + sinα sinβ = cos(α − β), which yields frequency translation, not AM with carrier.(d) Pure baseband; no modulation.(e) Linear addition of baseband and carrier is not amplitude modulation.


Common Pitfalls:

Confusing the correct AM form with DSB-SC; overlooking the modulation index limit and the need to scale m(t) in practice.


Final Answer:

x(t) = A_c [1 + m(t)] cos(2π f_c t)

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