Duty cycle of a step-down (buck) chopper Select the correct definition of duty cycle for an ideal step-down chopper switching with period T and on-time Ton. Also infer its relation to the output/input voltage ratio.
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AD = Ton / T (and ideally Vout/Vin = D)
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BD = Toff / T (and ideally Vout/Vin = D)
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CD = Vin / Vout
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DD = f_s / Vout where f_s is the switching frequency
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ED = Vout / (Vin)^2
Answer
Correct Answer: D = Ton / T (and ideally Vout/Vin = D)
Explanation
Introduction / Context:The duty cycle of a chopper determines the average output voltage. In a buck (step-down) converter, the control variable is the fraction of time the switch stays on within each switching period.
Given Data / Assumptions:
- Ideal components (no drops, no ripple for average relation).
- Switching period T with on-time Ton and off-time Toff.
Concept / Approach:By volt-second balance on the inductor in steady state, the average output voltage equals the input voltage multiplied by the duty cycle. Hence, duty cycle is defined as Ton/T and directly scales the output.
Step-by-Step Solution:Define D = Ton / T.Apply inductor volt-second balance: average inductor voltage over one period is zero.During on: V_L ≈ Vin − Vout; during off: V_L ≈ −Vout.Set D*(Vin − Vout) + (1 − D)*(−Vout) = 0 → Vout = D * Vin.
Verification / Alternative check:Simulation or measured average output of a PWM buck confirms proportionality to D for continuous conduction.
Why Other Options Are Wrong:Toff/T: That is 1 − D, not D.Vin/Vout or inverse powers: Dimensional/physical mismatch.f_s/Vout: Nonsense dimensionally (Hz/Volt).
Common Pitfalls:Confusing duty cycle with conduction ratio in discontinuous mode (where Vout relation deviates), or ignoring non-ideal drops that slightly reduce Vout.
Final Answer:D = Ton / T (and ideally Vout/Vin = D)