Transcription directionality — During RNA synthesis, what RNA sequence is produced from the DNA template strand 5′-T p A p G p C-3′ (written 5′→3′ on the template)?

Difficulty: Medium

Correct Answer: 5′-G p C p U p A-3′

Explanation:


Introduction:
Transcription produces RNA complementary to the DNA template and antiparallel to it. Getting orientation correct is essential for predicting RNA sequences from DNA and vice versa.


Given Data / Assumptions:

  • Template strand is explicitly given 5′→3′ as T–A–G–C.
  • RNA uses U instead of T.
  • Polymerases synthesize RNA 5′→3′ while reading the template 3′→5′.


Concept / Approach:
Because the provided template is written 5′→3′, we must first reverse its orientation to align with the polymerase reading direction. Complement bases accordingly and then express the RNA in the standard 5′→3′ direction.


Step-by-Step Solution:

1) Template (given) 5′→3′: T–A–G–C.2) Reverse to 3′→5′ for reading: C–G–A–T.3) Complement to RNA (5′→3′ product): G–C–U–A.4) Therefore, RNA sequence is 5′-G C U A-3′ (option b, noting U for uracil).


Verification / Alternative check:
Check against the non-template (coding) strand: it would be 5′-G C T A-3′ in DNA, so replacing T with U gives 5′-G C U A-3′ in RNA, matching the result.


Why Other Options Are Wrong:

a) Uses T instead of U and has wrong orientation.c) Contains T, not U, and mismatches base pairing.d) Incorrect base order; A U C G would pair with T A G C in the same orientation, which is not antiparallel.e) Not reported in the standard 5′→3′ product orientation requested.


Common Pitfalls:
Forgetting antiparallel orientation; writing T in RNA; failing to reverse the template before complementing.


Final Answer:
5′-G p C p U p A-3′.

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