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- Question
- A boat has to travel upstream 20 km distance from point X of a river to points Y. The total time taken by boat in travelling from point X to Y and Y to X is 41 min 40 s. What is the speed of the boat?
Options- A. 66 km/h
- B. 72 km/h
- C. 48 km/h
- D. Cannot be determined
- Correct Answer
- Cannot be determined
ExplanationLet x be the speed of the boat and y be the speed of the current.
Speed upstream = (x - y) km/h
Speed downstream = (x + y) km/h
According to the question,
20 /(x - y) + 20/(x + y) = 25/36
In this equation, there are two variables but only one equation. So, the value of x cannot be determined. - 1. In the following question, select the odd number group from the given alternatives.
Options- A. (143, 64)
- B. (232, 49)
- C. (719, 289)
- D. (462, 169) Discuss
- 2. The diference of two numbers is 20% of the larger number, if the smaller number is 20, then the larger number is :
Options- A. 15
- B. 25
- C. 35
- D. 45 Discuss
- 3. Sairam spent Rs. 38460 on the renovation of his home and Rs. 24468 on buying TV set and remained with 28% of the total amount. What was the total amount?
Options- A. Rs. 87400
- B. Rs. 68700
- C. Rs. 74000
- D. Rs. 94060 Discuss
- 4. Out of first 20 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is ?
Options- A. 16/19
- B. 1
- C. 3/2
- D. 17/20 Discuss
- 5. A trader marked the price of the T.V. 30% above the cost price of the T.V. and gave the purchaser 10% discount on the marked price, thereby gaining Rs.340. Find the cost price of the T.V ?
Options- A. Rs. 2000
- B. Rs. 1600
- C. Rs. 2200
- D. Rs. 2100 Discuss
- 6. In the following question, four number pairs are given. The number on left side of (?) is related to the number on the right side of (?) with some Logic/Rule/Relation. Three are similar on basis of same Logic/Rule/Relation. Select the odd one out from the given options.
Options- A. 3 ? 6
- B. 5 ? 10
- C. 7 ? 12
- D. 9 ? 18 Discuss
- 7. Ram sell his goods 25% cheaper than Shyam and 25% dearer than Bram. How much % is Bram's good cheaper than Shyam ?
Options- A. 60%
- B. 40%
- C. 50%
- D. 30% Discuss
- 8. If 5x = 30-y = 6z , then what is the value of (xy + yz + zx)/xyz?
Options- A. 0
- B. 1
- C. 2
- D. 3 Discuss
- 9. In the following question, select the odd word pair from the given alternatives
Options- A. White ? Colour
- B. Blue ? Colour
- C. Yellow ? Orange
- D. Black ? Colour Discuss
- 10. What percent decrease in salaries would exactly cancel out the 20 percent increase ?
Options- A. (16 + 2/3) %
- B. (15 + 2/3)%
- C. (14 +1/3)%
- D. (13 + 4/5)% Discuss
More questions
Correct Answer: (462, 169)
Correct Answer: 25
Explanation:
Let the large number be x.
Then x - 20 = 20x/100
=> x - x/5 = 20 => x = 25.
Correct Answer: Rs. 87400
Explanation:
Let the total amount he had with = Rs. p
From the given data,
p - 38460 - 24468 = 28p/100
p - 28p/100 = 24468 + 38460
72p/100 = 62928
72p = 62928 x 100
p = 62928 x 100/72
p = 87400
Hence, the total amount he had = p = Rs. 87400.
Correct Answer: 17/20
Explanation:
n(S) = 20
n(Even no) = 10 = n(E)
n(Prime no) = 8 = n(P)
P(E U P) = 10/20 + 8/20 - 1/20 = 17/20
Correct Answer: Rs. 2000
Explanation:
Let 'x' be the cost price.
Now Marked price = x + 30x/100 = 13x/10
10% discount = 10/100 x 13x/10 = 13x/100
Selling price = 13x/10 - 13x/100 = 117x/100
Given gain = 340
Here gain = 117x/100 - x = 17x/100 = 340 => x = Rs. 2000.
Correct Answer: 7 ? 12
Correct Answer: 40%
Explanation:
Lets say shyam sells at 100,
Since Ram sells 25% cheaper than Shyam,
Therefor Ram sells at less than 25% of100 or 75 rs.
Ram sells 25% dearer than Bram or 125% of Ram =100% of Bram or
125% of x (say x price of bram )=75rs.
or 100% of x =60rs.
hence price of bram is 60rs.
now Bram's good is cheaper than Shyam's as (100-60)x100/100% or 40%.
Hence Brams Good is 40% cheaper than that of Shyam's good.
Correct Answer: 0
Correct Answer: Yellow ? Orange
Correct Answer: (16 + 2/3) %
Explanation:
Let the orginal salary = Rs. 100. New's salary = Rs.120.
Decrease on 120 = 20. Decrease on 100 = [(20/120)*100]% = (16 + 2/3) %.
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