Difficulty: Medium
Correct Answer: 2 km/h
Explanation:
Introduction / Context:Equal distances with different times specify upstream and downstream effective speeds. Combine with the still-water speed identity to find the current.
Given Data / Assumptions:
Concept / Approach:Use b = (vd + vu)/2 and c = (vd − vu)/2 because vd = b + c and vu = b − c.
Step-by-Step Solution:
b = (vd + vu)/2 = (d/3 + d/9)/2 = (4d/9)/2 = 2d/9Set 2d/9 = 4 ⇒ d = 18 kmc = (vd − vu)/2 = (d/3 − d/9)/2 = (2d/9)/2 = d/9 = 18/9 = 2 km/hVerification / Alternative check:vu = b − c = 2 km/h ⇒ time upstream = 18/2 = 9 h; vd = b + c = 6 km/h ⇒ time downstream = 18/6 = 3 h; consistent.
Why Other Options Are Wrong:3, 4, 6 contradict the still-water speed condition when reconstructed.
Common Pitfalls:Trying to solve directly for speeds without relating them to distance; use the identities for sums and differences.
Final Answer:2 km/h.
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