Here, S1 = 8 km/h
and S2 = 16 km/h
? d1 =s1 x t1 = 8t1 ...(i)
and d2 = s2 x t2 = 16t2 ...(ii)
We know that,
t1 + t2 = 8 ...(iii)
and
d1 + d2 = 80 (given) ...(iv)
From Eqs.(i) and (ii) put the value of d1 and d2 in Eq. (iv), we get
d1 + d2 = 80
8t1 + 16t2 = 80
? 8t1 + 8t2 + 8t2 = 80
8(t1 + t2) + 8t2 = 80
From Eq (iii),
8 x 8 + 8t2 = 80
8t2 = 80 - 64 = 16
? t2 = 16/8 = 2h
? t1 = 8 - 2 = 6 h
? Distance travelled by foot = d1 = 8 x 6 = 48 km.
Let the amount of juice and water in original mixture '4x' litre and '3x' litre respectively.
According to given data,
4x/3x+6 =8/7
28x=24x+48
28x?24x=48
4x = 48
x = 12
Amount of juice = 4x = 4×12 = 48 litre.
Ratio of milk andwater = 4:1
Quantity of water = 35/5 = 7 litres
Quantity of milk = 35 X 4/5 = 28 litres
If 7 litre of water is added, new quantity of water = 14 litre
New ratio of milk and water = 28:14 = 2:1
Let the number be N
According to the question
N - 3N/4 = 163
? N/4 = 163
? N = 652
Let initial quantity be Q, and final quantity be F
F = Q(1 - 8/Q)
=> Q = 20
2|64009( 253 |4 |---------- 45|240 |225 |---------- 503| 1509 | 1509 |---------- | X |----------∴ √64009 = 253.
So, the required number is -128.
? = 6.39 x 128.948 + 5.215 ÷ 12.189 + 25.056
= 639 x 128.948 + 5.215 x (1/12.189) + 25.056
= 823.97772 + 0.427844778 + 25.056
= 849.4615648 ? 852
By the formula, speed= Distance/ Time
= (240 + 240)/27 x (18/5)
= 480/27 x 18/5 = 64 km/h
1 / .003718 = 10000 / 3.718
= 10000 x ( 1/3.718)
= 10000 x .2689
= 2689.
Efficiency of A = 4.16%
Efficiency of B = 1.6 x 4.16 = 6.66%
? Number of days required by B = 100/6.66 = 15 days
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