Average speed with two different speeds — ratio of distances: A man travels part of a journey at 20 km/h and the rest at 70 km/h. His overall average speed is 50 km/h. What is the ratio of the distance covered at 20 km/h to that covered at 70 km/h?

Difficulty: Medium

Correct Answer: 4 : 21

Explanation:


Introduction / Context:
When average speed over a whole trip is known and the trip has only two constant-speed segments, ratios can be derived without the absolute distance.


Given Data / Assumptions:

  • Speeds: v1 = 20 km/h, v2 = 70 km/h
  • Average over the entire journey: V_avg = 50 km/h
  • Let distances be d1 and d2 for the two legs.


Concept / Approach:
Average speed V_avg = (d1 + d2) / (d1/20 + d2/70). Let x = d1/d2 and solve for x.


Step-by-Step Solution:

(x + 1) / (x/20 + 1/70) = 50Denominator = (7x + 2)/140 ⇒ ratio = 140(x + 1)/(7x + 2)140x + 140 = 50(7x + 2) = 350x + 100⇒ 210x = 40 ⇒ x = 4/21


Verification / Alternative check:
Try d1 : d2 = 4 : 21 with any scaling; average recomputes to 50 km/h.


Why Other Options Are Wrong:
Other ratios fail to satisfy the average speed relationship.


Common Pitfalls:
Using time ratios instead of distance ratios in the average speed formula.


Final Answer:
4 : 21

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