Difficulty: Hard
Correct Answer: 307.5 km
Explanation:
Introduction / Context:When trains have cruising speeds and scheduled halts, the end-to-end time combines motion time and halt time. Here we compute the express’s total time for 600 km, then determine the local’s distance within the same duration.
Given Data / Assumptions:
Concept / Approach:Express motion time = 600/100 = 6 h. Number of halts during the run = 600/75 − 1 = 8 − 1 = 7 halts ⇒ 21 min. Total express time = 6 h 21 min = 381 min. In blocks, the local spends 30 min moving per 25 km plus 1 min halt = 31 min per full 25 km block.
Step-by-Step Solution:
Number of full local blocks in 381 min = floor(381/31) = 12Distance in full blocks = 12 * 25 = 300 kmRemaining time = 381 − 372 = 9 min ⇒ extra distance at 50 km/h = 50 * 9/60 = 7.5 kmTotal local distance = 300 + 7.5 = 307.5 kmVerification / Alternative check:If a stop were counted at the terminal, total express time would be 384 min, yielding 310 km for the local, which is not among the original best options—so excluding a terminal halt is consistent.
Why Other Options Are Wrong:400, 405, 415.5 km assume higher effective average or miscount halts; 307.25 km is a rounding artifact not supported by whole-block accounting.
Common Pitfalls:Counting a destination halt, or forgetting that the local’s final partial segment involves no halt unless a 25 km boundary is reached.
Final Answer:307.5 km
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