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Home Aptitude Time and Distance See What Others Are Saying!
  • Question
  • A thief sees a jeep at a distance of 250 m, coming towards him at 36 km/h. Thief takes 5 seconds to realise that there is nothing but the police is approaching him by the jeep and start running away from police at 54 km/h. But police realise after 10 seconds, when the thief starts running away, that he is actually a thief and gives chase at 72 km/h. how long after thief saw police did police catchup with him and what is the distance police had to travel to do so?


  • Options
  • A. 50 sec, 1000 m
  • B. 65 sec, 1150 m
  • C. 65 sec, 1300 m
  • D. 45 sec, 1050 m

  • Correct Answer
  • 65 sec, 1150 m 

    Explanation

    Initial speed of police = 10 m/s
    Increased speed of police = 20 m/s
    Speed of thief = 15 m/s
    Initial difference between thief and police = 250 m
    After 5 seconds difference between thief and police = 250 - (5 x 10) = 200 m
    After 10 seconds more, the difference between thief and police = 200 + (5 x 10) = 250 m.
    Now, the time required by police to catch the thief = 250/5 = 50 s
    Distance travelled = 50 x 20 = 1000 m
    Total time = 50 + 15 = 65 sec
    Total distance = 1000 + (15 x 10) = 1150 m


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