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- Question
- 10 men and 8 women together can complete a work in 5 days. Work done by one women in day is equal to half the work done by man in 1 day. How many days will it take for 4 men and 6 women to complete that work?
Options- A. 12 days
- B. 10 days
- C. 82/3
- D. 43/4 days
- Correct Answer
- 10 days
ExplanationAccording to the question,
1 man = 2 women
? 10 men + 8 women = (20 + 8) women = 28 women
4 men + 6 women = (8 + 6) women = 14 women
Given, M1 = 28, M2 = 14, D1 = 5, D2 = ?
and W1 = W2 = 1
According to the formula, M1D1W2= M2D2W1
? 28 x 5 x 1 = 14 x D2 x 1
? D2 = (28 x 5)/14 = 10 days - 1. A takes twice as much time as B, and C take thrice as much time as B to finish a work. Working together, they can finish the work in 12 days. Find the number of days needed for A to do the work alone.
Options- A. 20
- B. 22
- C. 33
- D. 44 Discuss
- 2. 16 children and 24 men complete a certain work for 18 days. If each child takes twice the time taken by a man to finish the work in how many days will 24 men finish the same work?
Options- A. 12 days
- B. 24 days
- C. 36 days
- D. 48 dyas Discuss
- 3. A, B and C can do a piece of work in 18, 24 and 36 days, respectively. They work alternately, first day C, second day B and third day A, fourth day C and so on. How many days will be needed to complete the work like this way?
Options- A. 18
- B. 20
- C. 24
- D. 30 Discuss
- 4. 6 men can do a piece of work in 12 days while 8 women can do the same work in 18 days. The same work can be done by 18 children in 10 days. 4 men 12 women and 20 children work together for 2 days. If only men have to complete remaining work in 1 day, then find the required number of men.
Options- A. 36
- B. 24
- C. 18
- D. couldn't be determind Discuss
- 5. A can complete a work in 20 days and B in 30 days. A worked alone for 4 days and then B complete the remaining work alone with C in 18 days. In how many days can C working alone complete the work?
Options- A. 12
- B. 68
- C. 72
- D. 90 Discuss
- 6. 5 men started working to complete a work in 15 days. After 5 days, 10 women are accompanied by to them to complete the work in next 5 days. If the work is to be done by women only, when could the work be over, if 10 women have started it?
Options- A. 10 days
- B. 18 days
- C. 15 days
- D. 12 days Discuss
- 7. A contract is to be complete in 50 days and 105 men were set to work, each working 8 h a day. After 25 days, 2/5th of the work is finished. How many additional men be employed, so that the work may be completed on time, each man now working 9 h a day?
Options- A. 34
- B. 36
- C. 35
- D. 37 Discuss
- 8. If 14 men and 12 boys can finish work in 4 days, while 8 men and 16 boys can finish the same work in 5 days. Compare the 1 days work of 1 man and 1 boy.
Options- A. 2
- B. 11/2
- C. 1/2
- D. 3 Discuss
- 9. In a factory, there are equal number of women and children. Women work for 6 h a days and children for 4 h a day. During festival time, the work load goes up by 50%. The government rule does not allow children to work for more then 6 h a day. If they are equally efficient and the extra work is done by women, then extra hours of work put in by women everyday are?
Options- A. 5
- B. 3
- C. 4
- D. 9 Discuss
- 10. 3 women and 18 children together take 2 days to complete a piece of work. How many days will 9 children alone take to complete the piece of work, if 6 women alone can complete the piece of work in 3 days?
Options- A. 9
- B. 7
- C. 5
- D. 6 Discuss
Time and Work problems
Search Results
Correct Answer: 44
Explanation:
Let time taken by B = N
Then, time taken by A = 2N
and time taken by C = 3N
According to the question,
(1/N) + (1/2N) + (1/3N) = 1/12
? 1 + (1/2) + (1/3) = N/12
? (6 + 3 + 2)/6 = N/12
? 11 = N/2
? N = 22
? Required number of days = 2N = 2 x 22 = 44 days
Correct Answer: 24 days
Explanation:
According to the question,
2 children = 1 man
? (16 children + 24 men) = (8 + 24) men = 32 men
Given M1 = 32, M2 = 24, D1 = 18, D2 = ?
and W1 = W2 = 1
According to the formula, M1D1W2 = M2D2W1
? 32 x 18 x 1 = 24 x D2 x 1
? D2 = (32 x 18)/24 = 8 x 3 = 24 days
Correct Answer: 24
Explanation:
Work done in first in 3 days
= (1/18) + (1/24) + (1/36) = (4 + 3 + 2)/72 = 1/8
? Time taken to complete 1/8 part of work = 3 days
? Time taken to complete the whole work = 3 x 8 = 24 days
Correct Answer: 36
Explanation:
6 x 12 men = 8 x 18 women = 18 x 10 children
? 12 men = 24 women = 30 children
? 2 men = 4 women = 5 children
Now, 4 men + 12 women + 20 children = 4 men + 6 men + 8 men = 18 men
Time to do remaining work in 1 man = (6 x 12 - 18 x 2) = 36 days
? Required number of men to finish the work in 1 days = 36
Correct Answer: 90
Explanation:
Work done by A in 4 days = 4/20 = 1/5
? Remaining work = 1 - 1/5 = 4/5
Let C can working alone complete the work in N days .
According to the question,
18/30 + 18/N = 4/5
? 18(N + 30) x 5 = 4 x 30 x N
? 90N + 2700 = 120N
? 30N = 2700
? N = 90 days
Correct Answer: 15 days
Explanation:
According to the question,
5 men's 1 day's work = 1/15 .....(i)
? 5 men's 5 day's work = (1/15) x 5 = 1/3
? Remaining work = 1 - (1/3) = 2/3
5 men + 10 women can do 2/3 of the work in 5 days.
? 5 men + 10 women can do the whole of the work in 15/2 days.
? (5 men + 10 women's) 1 day's work = 2/15 .......(ii)
10 women 1 days work = (2/15) - 5 men's 1 day's work
= (2/15) - (1/15)
= 1/15
? 10 women can finish the work in 15 days
Correct Answer: 35
Explanation:
According to the formula
M1D1T1/W1= M2D2T2/W2
Given M1 = 105 D1 = 25 T1 = 8 W1 = 2/5
Now let the additional men be N
Then, M2 = 105 + N, T2 = 9, D2 = 25 and W2 =1 - (2/5) = 3/5
On putting these value in the above formula
(105 x 25 x 8) / (2/5) = [(105 + N) x 25 x 9] / (3/5)
? (105 x 8) / 2 = (105 + N) x (9/3)
? 105 x 4 = (105 + N) x 3
? 105 x 4 = 105 x 3 +3N
? 3N = 105
? N = 35 men
Correct Answer: 2
Explanation:
Here, a1 = 14, b1 = 12, p = 4, a2 = 8, b2 = 16 and q = 5
One days work of 1 man/One days of 1 boy
= (qb2 - pb1) / ( pa1 - qa2)
= [5 x 16 - 4 x 12] / [ 4 x 14 - 5 x 8]
= (80 - 48) / (56 - 40)
= 32/16
= 2
Correct Answer: 3
Explanation:
Let extra hours a day are N.
According to the formula,
(M1D1T1) / W1 = (M2D2T2) / W2
? [1 x 1 x (6 + 4)] / 1 = [1 x 1 x (6 + 6 + N)] / 11/2
? (3/2) x 10 = 12 + N
? 15 = 12 + N
? N = 15 - 12 = 3
Extra hours of works everyday are 3.
Correct Answer: 6
Explanation:
Since, 3 women + 18 children complete work in 2 days. Therefore, (3 x 2) women + (18 x 2) children complete work in 1 days i.e, 6 women + 36 children complete work in 1 day.
Work of 36 children for 1 day = 1 - (1/3) = 2/3
[? work of 6 women for 1 day = 1/3]
? 36 children do 2/3 part of the work in 1 day.
36 children can do the work in 3/2 days.
9 children can do the the work in (3/2) x 4 = 6 days
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