Let the total number of subbscribers be x.
Then, x2 = 2582449
? x = ?2582449 = 1607
Let the total number of soliders in front be x. Then, total number of soliders in form of solid square = x2
According to the question, x2 + 31 = 16160
? x2 = 16129 ? x = ?16129
? x = 127
Let the number be x.
Then, accordingto the question,
x2 = (75.15)2 - (60.12)2
? x2 = 5647.52 - 3614.41
? x2 = 2033.11
? x = 45.09
74088 = 2 x 2 x 2 x 3 x 3 x 3 x 7 x 7 x 7
= (2 x 2) x (3 x 3) x (7 x 7) x ( 2 x 3 x 7)
? Least number which should be multiplied to 74088 to make it a perfect suqare = 2 x 3 x 7 = 42
?10 and ?8 = 101/4 and 81/3
Since, LCM of 4 and 3 is 12.
? 101/4 = 103/12 = (103)1/12 = (1000)1/12 = 12?1000
and 81/3 = 84/12 = (84)1/12 (4096)1/2 = 12?4096
? 4096 > 1000
Hence, 81/3 >101/4
? ?8 > ?10
Let the number be x.
According to the question,
x2 + (14)3 = 4425
? x2 = 4425 - (14)3
? x2 = 4425 - 2744
? x2 = 1681
? x = ?1681 = 41
Total collected amount = Rs. 29791
? Total number of student = ?29791 = 31
xy = [(?2 + 1)/(?2 - 1)] x [(?2 - 1)/(?2 + 1)] = 1
? 3(xy + 1) = 3(1 + 1) = 6
Now, x + y = [(?2 + 1)/(?2 - 1)] + [(?2 - 1)/(?2 + 1)]
= (?2 + 1)2 + (?2 - 1)2 / (?2 - 1) (?2 + 1)
= (2 + 1 +2?2) + (2 + 1 - 2?2) / (2 - 1) = 6
? 3(xy + 1) = x + y
Ans. LCM of 21, 36 and 66 = 2772
Now, 2772 = 2 x 2 x 3 x 3 x 7 x 11
To make it a perfect square, it must be multiplied by 77 [for (7 x 11)].
? Required number = 22 x 32 x 72 x 112 = 213444
7777 - N must be a perfect square.
Now, using the option, we find that N = 33
7777 - 33 = 7744 is perfect square.
Let the number of bangles be x. Then, x - 38 is a perfect square and x + 25 is a perfect square.
Now, using the option, we find that x = 999
999 - 38 = 961 is a perfect square.
999 + 25 = 1024 is a perfect square
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