Discussion
Home ‣ Aptitude ‣ Average See What Others Are Saying!
- Question
- The average of class in 35 yr. 6 new students with an average age of 33 yr. joined in that class, there by decreasing the average by half year. The original strength of the class was
Options- A. 14
- B. 18
- C. 16
- D. 20
- Correct Answer
- 18
ExplanationLet the number of students in the class = N
According to the question,
(35N + 6 x 33) / (N + 6) = 35 - (1/2)
? 35N + 198 = 34.5 (N + 6)
? 35N +198 = 34.5N + 207
? 0.5N = 207 -198N = 9/0.5 = 18
? N = 18 days
- 1. What percent of 7.2 kg is 18 gms?
Options- A. .025%
- B. .25%
- C. 2.5%
- D. 25% Discuss
- 2. Find the cube root of 19683.
Options- A. 25
- B. 26
- C. 28
- D. 27 Discuss
- 3. A cost of cultivating a square field at a rate of ? 135 per hectare is ? 1215. The cost of putting a fence around it at the rate of 75 paise per meter wouldbe
Options- A. ? 360
- B. ? 810
- C. ? 900
- D. ? 1800 Discuss
- 4. Find the sum of place and face values of 8 in 43836
Options- A. 88
- B. 808
- C. 880
- D. 888 Discuss
- 5. Find the quotient when (a-1 - 1) is divided by (a - 1).
Options- A. 2/a
- B. 2a
- C. a/2
- D. -1/a Discuss
- 6. Find the least number which when divided by 12, 15, 20 and 24 leaves the same remainder 2 in each case?
Options- A. 122
- B. 120
- C. 124
- D. 126 Discuss
- 7. If the area of a semi-circle be 77 sq m, find its perimeter.
Options- A. 36 m
- B. 42 m
- C. 48 m
- D. 54 m Discuss
- 8. What is the remainder in the expression 29 18? 26
Options- A. 29
- B. 26
- C. 18
- D. 0 Discuss
- 9. The whole surface area of a rectangular block is 8788 sq cm. If length, breadth and height are in ratio of 4 : 3 : 2, then find the length.?
Options- A. 26 cm
- B. 52 cm
- C. 104 cm
- D. 13 cm Discuss
- 10. In a two-digit number, the digit at the unit's place is 1 less than twice the digit at the ten's place. If the digits at unit's and ten's place are interchanged, the difference between the new and the original number is less than the original number by 20. The original number is
Options- A. 47
- B. 59
- C. 23
- D. 35 Discuss
More questions
Correct Answer: .25%
Explanation:
7.2 kg = 7.2 x 1000000 gm = 7200000 gms
Required percentage = (18/7200000) x 100 % = 0.25%
Correct Answer: 27
Explanation:
In 19683, 19 lies between 23 and 33, so left digit is 2 and 683 ends with 3, so right digit is 7.
thus 27 is a cube root of 19683.
Correct Answer: ? 900
Explanation:
Area of the field =1215/135 = 9 hec
= 90000 m2 [1 hec =10000 m2]
? Side of the field = ?90000 = 300 m
Perimeter of the field = 4 x 300 = 1200 m
Now, cost of putting a fence around field = (1200 x 75)/100 = ? 900
Correct Answer: 808
Explanation:
Place value of 8 = 800
Face value of 8 = 8
? required sum = 800 + 8
Correct Answer: -1/a
Explanation:
Given equation is
a-1 - 1
Apply the law of Fractional Exponents and Laws of Exponents
x-y = 1/xy
? a-1 - 1 = 1/a - 1
? a-1 - 1 = (1 - a)/a
Now divide by a - 1 in above equation,
? ( a-1 - 1 ) ÷ (a - 1) = (1 - a)/a ÷ (a - 1)
? ( a-1 - 1 ) ÷ (a - 1) = (1 - a)/a x 1/ (a - 1)
? ( a-1 - 1 ) ÷ (a - 1) = -1x (a - 1)/a x 1/ (a - 1)
? ( a-1 - 1 ) ÷ (a - 1) = -1/a
? Required quotient = -1/a.
Correct Answer: 122
Explanation:
Required number = LCM of (12, 15, 20, 24) + 2
= 120 + 2 = 122
Correct Answer: 36 m
Explanation:
According to the question,
Area of semi- circle = 77 m
(1/2) x ? x r2 = 77
? r2 = (77 x 2 x 7)/22
? r = 7m
?Circumference of semi- circle =?r + 2r
= ( ? + 2)r
= [(22/7) + 2] x 7
= 36 m
Correct Answer: 18
Explanation:
It is clear from expression is that remainder is 18
Correct Answer: 52 cm
Explanation:
Let length, breadth and height be 4k, 3k and 2k, respectively.
Whole surface area = 2(lb + bh + lh)
? (lb + bh + lh) = 8788/2 = 4394
? (4 x 3 + 3 x 2 + 2 x 4 ) k2 = 4394
? 26k2 = 4394
? k2 = 169
? k = 13
? Length = 4k = 4 x 13 = 52 cm
Correct Answer: 47
Explanation:
let us assume the ten's digit number be x and unit's place digit be y.
Then two digit Original Number = 10x + y
According to question ? y = 2x - 1 ................(1)
When digits are interchanged then new number = 10y + x
If the digits at unit's and ten's place are interchanged, the difference between the new and the original number is less than the original number by 20,
New Number - Original Number = Original number - 20
? 10y + x - (10x + y) = 10x + y - 20
? 10y + x - 10x - y - 10x - y = - 20
? 8y - 19x = - 20
? 19x - 8y = 20 ...................(2)
Put the value of y from equation (1) in above equation (2).
? 19x - 8(2x - 1) = 20
? 19x - 16x - 8 = 20
? 7x = 20 + 8
? 7x = 28
? x = 28/7
? x = 4
Put the value of y in equation (1)
From (i) y = 2 x 4 -1 = y = 7
? original number = 10x + y =10 x 4 + 7 = 47.
Comments
There are no comments.More in Aptitude:
Programming
Copyright ©CuriousTab. All rights reserved.