LCM of two coprimes is equal to their product.
Required HCF = (HCF of numerators) / (LCM of denominators)
= (HCF of 1, 3 and 4) / (LCM of 2, 4, and 5)
= 1/20
We know that,
HCF of fractions = (HCF of numerators) / (LCM of denominators)
? Required HCF = (HCF of 4 and 7) / (LCM of 5 and 15)
=1/15
132 = 2 x 2 x 3 x 11
240 = 2 x 2 x 2 x 2 x 3 x 5
228 = 2 x 2 x 3 x 19
Hence, HCF of 132, 204 and 228 = 2 x 2 x 3 = 12
LCM of (12,18, 36) = 36
? A number greater than 300 on dividing by 36 leaves a remainder 4 = (36 x 9) + 4 = 328
Next numbe r = 328 + 36 = 364
? Sum of number = 328 + 364 = 692
The HCF of [(480 - 390), (620 - 480), (620 - 390)]
= HCF of 90, 140, 230 = 10
Given, LCM of two number = 2376
HCF of two number = 33
One of the number = 297
? (HCF of two numbers) x (LCM of two numbers) = (First number) x (Second number)
? Second number = (33 x 2376)/297
= 264
Given,
LCM = 1989, HCF = 13
1st number = 117 and
2nd number = ?
According to the formula,
Product of LCM and HCF = Product of two numbers
? 1989 x 13 = 117 x ?
? = (1989 x 13)/117
? = 221
Let the numbers are 3N, 4N and 5N.
Where, N = HCF
Then, LCM = 60N
According to the question,
60N = 1200
? N = 20
Let numbers be 10N, 12N, 15N and 18N.
Then, LCM = 180N and HCF = N
Hence, required LCM = 180 x 3 = 540
By Hit and Trial
From option (d), we can say that the HCF of 36 and 24 is 12 and it is also satisfies the given condition
a > b > 12
? a = 36 and b = 24
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.