Internally pressurised cylindrical vessels: comparing closures of the same material and thickness, which head shape can withstand the highest internal pressure before reaching the same membrane stress limits?

Chemical Engineering Process Equipment and Plant Design Difficulty: Easy
Choose an option
Answer

Correct Answer: hemispherical

Explanation

Introduction / Context:Pressure vessel ends (heads) convert internal pressure into membrane stresses. For a given material and thickness, geometry strongly influences the stress distribution. Identifying the most efficient head helps reduce weight or increase allowable design pressure.

Given Data / Assumptions:

  • All heads have identical nominal thickness and are made from the same material.
  • Elastic membrane theory applies; local discontinuities at knuckles are neglected for comparison.
  • Internal pressure loading only; no external loads or vacuum buckling.

Concept / Approach:Hemispherical heads develop uniform membrane stresses and have the most favorable curvature in both principal directions. As a result, for the same thickness, the allowable internal pressure is highest. Ellipsoidal (2:1) heads are next best, followed by torispherical or conical. Flat plates are worst because they carry bending in addition to membrane stresses.

Step-by-Step Solution:Rank shapes by curvature efficiency: hemispherical > ellipsoidal > conical > flat.For equal thickness, the head with the lowest stress at a given pressure can withstand the highest pressure.Select hemispherical as best performer.

Verification / Alternative check:Design codes use larger allowable pressure or smaller required thickness for hemispherical heads than for ellipsoidal/torispherical heads under the same conditions.

Why Other Options Are Wrong:Ellipsoidal (2:1): efficient but not as strong as hemispherical for the same thickness.Conical: stress concentrations at the knuckle; lower pressure capacity.Flat plate: carries bending, lowest pressure capacity for a given thickness.

Common Pitfalls:Comparing unequal thicknesses; ignoring required knuckle radii and code joint efficiencies.

Final Answer:hemispherical

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