An enzyme has a Km of 4.7 x 10-5M. If the Vmax of the preparation is 22m moles liter-1 min-1, what velocity would be observed in the presence of 2.0 x 10-4M substrate and 5.0 x 10-5M of a competitive inhibitor?
Options
A. 13.54? moles liter-1min-1
B. 6.68? moles liter-1min-1
C. 7.57? moles liter-1min-1
D. 17.8? moles liter-1min-1
Correct Answer
13.54? moles liter-1min-1
More questions
1. If biomass yields are constant, then the biomass productivity of a culture grown in continuous reactor will
Options
A. always decrease with dilution rate
B. increase with dilution rate until washout
C. remain constant irrespective of the dilution rate
Correct Answer: decreases the productivity of the fermenter
4. The cellular productivity in a continuous stirred tank fermenter (CSTF) increases with an increase in the dilution rate and reaches a maximum value. If the dilution rate is increased beyond the maximum point, the productivity will