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  • Question

  • An enzyme has a Km of 4.7 x 10-5M. If the Vmax of the preparation is 22m moles liter-1 min-1, what velocity would be observed in the presence of 2.0 x 10-4M substrate and 5.0 x 10-5M of a competitive inhibitor?


  • Options
  • A. 13.54? moles liter-1min-1
  • B. 6.68? moles liter-1min-1
  • C. 7.57? moles liter-1min-1
  • D. 17.8? moles liter-1min-1

  • Correct Answer
  • 13.54? moles liter-1min-1 

    • Enzymes and Kinetics problems

    Search Results

    • 1. The slope of Lineweaver Burk plot for Michaelis Menten equation is

    • Options
    • A. Vmax/Km
    • B. Km/Vmax
    • C. 1/Km
    • D. Km.Vmax
      • Discuss
    • 2. Which of the following statement(s) regarding enzymes, is/are false?

    • Options
    • A. Enzymes are always proteins that function as catalysts
    • B. Enzymes provide activation energy for reactions
    • C. Enzyme activity can be regulated
    • D. Enzymes may be used many times for a specific reaction
      • Discuss
    • 3. The equation for the rate of product formation for simple enzyme reaction is given by (Where rmax, maximum reaction rate, Cs substrate concentration, Cp product concentration ES, CES enzyme-substrate concentration)

    • Options
    • A. rp = rmax Cs/(Km+Cs)
    • B. rp= rmax CES/(Km+ CES)
    • C. rp = rmax Cs/(Km+CES)
    • D. rp = rmax Cs/(Km+Cp)
      • Discuss
    • 4. In the steady state the material balance equation for any component of a system is

    • Options
    • A. rate of addition + rate of removal - rate of formation = 0
    • B. rate of addition - rate of removal + rate of formation = 0
    • C. rate of addition + rate of removal + rate of formation = 0
    • D. none of the above
      • Discuss
    • 5. Which of the following refers to pseudo steady state?

    • Options
    • A. d(CE)/dt = 0
    • B. d(Cp)/dt = 0
    • C. d(CES)/dt = 0
    • D. d(Cs)/dt = d(CES)/dt
      • Discuss
    • 6. For an enzyme that displays Michaelis-Menten kinetics, the reaction velocity (as a fraction of Vmax) observed at [S] = 2 KM will be

    • Options
    • A. 0.09
    • B. 0.33
    • C. 0.66
    • D. 0.91
      • Discuss
    • 7. The usual method(s) to solve rate equation of simple enzyme kinetics is/are

    • Options
    • A. Michaelis Menten approach
    • B. Briggs-Haldane approach
    • C. Numerical solution approach
    • D. all of these
      • Discuss
    • 8. When an enzyme is functioning at Vmax, the rate of the reaction is limited by

    • Options
    • A. the number of collisions between enzyme and substrate
    • B. the number of substrate molecules in the reaction
    • C. the concentration of the substrate
    • D. the rate at which the enzyme can convert substrate to product
      • Discuss
    • 9. If a reaction occurs in the absence of inhibitor with rate ?0 and in the presence of inhibitor with rate ?i, the degree of inhibition is defined as

    • Options
    • A. (?0 - ?i)/?0
    • B. (?0 + ?i)/?0
    • C. (?0?i)/?0
    • D. (?0-?i)/?i
      • Discuss
    • 10. Which of the following step is assumed to be the slowest step in the Michaelis Menten equation?

    • Options
    • A. The substrate consuming step
    • B. The product releasing step
    • C. Formation of enzyme substrate complex
    • D. None of these
      • Discuss

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