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What will be the output of the program? #include int main() { float *p; printf("%d\n", sizeof(p)); return 0; }

Q: What will be the output of the program? #include int main() { float *p; printf("%d\n", sizeof(p)); return 0; }

sizeof(x) returns the size of x in bytes. float *p is a pointer to a float. In 16 bit compiler, the pointer size is always 2 bytes. In 32 bit compiler, the pointer size is always 4 bytes.

2 in 16bit compiler, 4 in 32bit compiler
4 in 16bit compiler, 2 in 32bit compiler
4 in 16bit compiler, 4 in 32bit compiler
2 in 16bit compiler, 2 in 32bit compiler

Correct Answer: 2 in 16bit compiler, 4 in 32bit compiler

Explanation:

sizeof(x) returns the size of x in bytes.
float *p is a pointer to a float.

In 16 bit compiler, the pointer size is always 2 bytes.
In 32 bit compiler, the pointer size is always 4 bytes.

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What will be the output of the program? #include int main() { float *p; printf("%d\n", sizeof(p)); return 0; }

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