What will be the output of the program? #include #include int main() { printf("%f ", sqrt(36.0)); return 0; }

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Accepted Answer

printf("%f ", sqrt(36.0)); It prints the square root of 36 in the float format(i.e 6.000000).

Declaration Syntax: double sqrt(double x) calculates and return the positive square root of the given number…

What will be the output of the program? #include<stdio.h> #include<math.h> int main() { printf("%f\n", sqrt(36.0)); return 0; }