What will be the output of the program? #include #include int main() { printf("%f ", sqrt(36.0)); return 0; }

Q: What will be the output of the program? #include #include int main() { printf("%f\n", sqrt(36.0)); return 0; }

printf("%f\n", sqrt(36.0)); It prints the square root of 36 in the float format(i.e 6.000000). Declaration Syntax: double sqrt(double x) calculates and return the positive square root of the given number.

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printf("%f
", sqrt(36.0)); It prints the square root of 36 in the float format(i.e 6.000000). Declaration Syntax: double sqrt(double x) calculates and return the positive square root of the given number.

What will be the output of the program? #include #include int main() { printf("%f\n", sqrt(36.0)); return 0; }

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