What will be the output of the program? #include #include int main() { printf("%d, %d, %d ", sizeof(3.14f), sizeof(3.14), sizeof(3.14l)); return 0; }

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Accepted Answer

sizeof(3.14f) here '3.14f' specifies the float data type. Hence size of float is 4 bytes.

sizeof(3.14) here '3.14' specifies the double data type. Hence size of float is 8 bytes.

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What will be the output of the program? #include<stdio.h> #include<math.h> int main() { printf("%d, %d, %d\n", sizeof(3.14f), sizeof(3.14), sizeof(3.14l)); return 0; }