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- Question
Add the following BCD numbers.
0110 0111 1001 0101 1000 1000
Options- A. 0000 1011 0000 1111 0001 0001
- B. 0001 0001 0001 0101 0001 0001
- C. 0000 1011 0000 1111 0001 0111
- D. 0001 0001 0001 0101 0001 0111
- Correct Answer
- 0001 0001 0001 0101 0001 0111
- 1. When multiplying 13 × 11 in binary, what is the third partial product?
Options- A. 1011
- B. 00000000
- C. 100000
- D. 100001 Discuss
- 2. An 8-bit register may provide storage for two's-complement codes within which decimal range?
Options- A. +128 to ?128
- B. ?128 to +127
- C. +128 to ?127
- D. +127 to ?127 Discuss
- 3. Divide the following binary numbers.
Options- A. 0000 0010 0000 0010 1000 1111
- B. 0000 0010 0001 0010 0000 0100
- C. 0000 0011 0000 0010 0000 0100
- D. 0000 0010 0000 0010 0000 0100 Discuss
- 4. In VHDL, what is a GENERATE statement?
Options- A. The start statement of a program
- B. Not used in VHDL or ADHL
- C. A way to get the computer to generate a program from a circuit diagram
- D. A way to tell the compiler to replicate several components Discuss
- 5. What is the difference between a full-adder and a half-adder?
Options- A. Half-adder has a carry-in.
- B. Full-adder has a carry-in.
- C. Half-adder does not have a carry-out.
- D. Full-adder does not have a carry-out. Discuss
- 6. Could the sum output of a full-adder be used as a two-bit parity generator?
Options- A. Yes
- B. No Discuss
- 7. Perform the following hex subtraction: ACE16 ? 99916 =
Options- A. 23516
- B. 13516
- C. 03516
- D. 33516 Discuss
- 8. Add the following binary numbers.
0010 0110 0011 1011 0011 1100 +0101 0101 +0001 1110 +0001 1111
Options- A. 0111 1011 0100 0001 0101 1011
- B. 0111 1011 0101 1001 0101 1011
- C. 0111 0111 0101 1001 0101 1011
- D. 0111 0111 0100 0001 0101 1011 Discuss
- 9. Subtract the following hexadecimal numbers.
47 34 FA ?25 ?1C ?2F
Options- A. 22 18 CB
- B. 22 17 CB
- C. 22 19 CB
- D. 22 18 CC Discuss
- 10. For a 4-bit parallel adder, if the carry-in is connected to a logical HIGH, the result is:
Options- A. the same as if the carry-in is tied LOW since the least significant carry-in is ignored.
- B. that carry-out will always be HIGH.
- C. a one will be added to the final result.
- D. the carry-out is ignored. Discuss
Digital Arithmetic Operations and Circuits problems
Search Results
Correct Answer: 00000000
Correct Answer: ?128 to +127
Correct Answer: 0000 0010 0000 0010 0000 0100
Correct Answer: A way to tell the compiler to replicate several components
Correct Answer: Full-adder has a carry-in.
Correct Answer: Yes
Correct Answer: 13516
Correct Answer: 0111 1011 0101 1001 0101 1011
Correct Answer: 22 18 CB
Correct Answer: a one will be added to the final result.
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