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Home ‣ Digital Electronics ‣ Digital Arithmetic Operations and Circuits Comments
  • Question

  • The carry propagation delay in full-adder circuits:


  • Options
  • A. is normally not a consideration because the delays are usually in the nanosecond range.
  • B. decreases in a direct ratio to the total number of FA stages.
  • C. is cumulative for each stage and limits the speed at which arithmetic operations are performed.
  • D. increases in a direct ratio to the total number of FA stages but is not a factor in limiting the speed of arithmetic operations.

  • Correct Answer
  • is cumulative for each stage and limits the speed at which arithmetic operations are performed. 

    • Digital Arithmetic Operations and Circuits problems

    Search Results

    • 1. Find the 2's complement of ?1101102.

    • Options
    • A. 1101002
    • B. 1010102
    • C. 0010012
    • D. 0010102
      • Discuss
    • 2. The 2's-complement system is to be used to add the signed binary numbers 11110010 and 11110011. Determine, in decimal, the sign and value of each number and their sum.

    • Options
    • A. ?113 and ?114, ?227
    • B. ?14 and ?13, ?27
    • C. ?11 and ?16, ?27
    • D. ?27 and ?13, ?40
      • Discuss
    • 3. Subtract the following binary numbers.

      0101 1000   1010 0011   1101 1110
      ?0010 0011   ?0011 1000   ?0101 0111

    • Options
    • A. 0011  0100    0110  1010    1000  0110
    • B. 0011  0101    0110  1011    1000  0111
    • C. 0011  0101    0110  1010    1000  0111
    • D. 0011  0101    0110  1010    1000  0110
      • Discuss
    • 4. Convert each of the following signed binary numbers (two's-complement) to a signed decimal number.
      00000101        11111100        11111000

    • Options
    • A. ?5    +4    +8
    • B. +5    ?4    ?8
    • C. ?5    +252    +248
    • D. +5    ?252    ?248
      • Discuss
    • 5. The truth table for a full adder is shown below. What are the values of X, Y, and Z?

    • Options
    • A. X = 0, Y = 1, Z = 1
    • B. X = 1, Y = 1, Z = 1
    • C. X = 1, Y = 0, Z = 1
    • D. X = 0, Y = 0, Z = 1
      • Discuss
    • 6. Why is a fast-look-ahead carry circuit used in the 7483 4-bit full-adder?

    • Options
    • A. to decrease the cost
    • B. to make it smaller
    • C. to slow down the circuit
    • D. to speed up the circuit
      • Discuss
    • 7. Convert each of the signed decimal numbers to an 8-bit signed binary number (two's-complement).
      +7        ?3        ?12

    • Options
    • A. 0000  0111    1111  1101    1111  0100
    • B. 1000  0111    0111  1101    0111  0100
    • C. 0000  0111    0000  0011    0000  1100
    • D. 0000  0111    1000  0011    1000  1100
      • Discuss
    • 8. What are constants in VHDL code?

    • Options
    • A. Fixed numbers represented by a name
    • B. Fixed variables used in functions
    • C. Fixed number types
    • D. Constants do not exist in VHDL code.
      • Discuss
    • 9. What distinguishes the look-ahead-carry adder?

    • Options
    • A. It is slower than the ripple-carry adder.
    • B. It is easier to implement logically than a full adder.
    • C. It is faster than a ripple-carry adder.
    • D. It requires advance knowledge of the final answer.
      • Discuss
    • 10. Which of the statements below best describes the given figure?


    • Options
    • A. Half-carry adder; Sum = 0, Carry = 1
    • B. Half-carry adder; Sum = 1, Carry = 0
    • C. Full-carry adder; Sum = 1, Carry = 0
    • D. Full-carry adder; Sum = 1, Carry = 1
      • Discuss

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