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Home ‣ Java Programming ‣ Exceptions See What Others Are Saying!
  • Question

  • What will be the output of the program? 
    public class X 
{  
    public static void main(String [] args) 
    {
        try 
        {
            badMethod();  
            System.out.print("A"); 
        }  
        catch (Exception ex) 
        {
            System.out.print("B");  
        } 
        finally 
        {
            System.out.print("C"); 
        } 
        System.out.print("D"); 
    }  
    public static void badMethod() 
    {
        throw new Error(); /* Line 22 */
    } 
}


  • Options
  • A. ABCD
  • B. Compilation fails.
  • C. C is printed before exiting with an error message.
  • D. BC is printed before exiting with an error message.

  • Correct Answer
  • C is printed before exiting with an error message. 

    Explanation
    Error is thrown but not recognised line(22) because the only catch attempts to catch an Exception and Exception is not a superclass of Error. Therefore only the code in the finally statement can be run before exiting with a runtime error (Exception in thread "main" java.lang.Error).

    More questions

    • 1. What will be the output of the program (in jdk1.6 or above)? 
      public class BoolTest 
{
    public static void main(String [] args) 
    {
        Boolean b1 = new Boolean("false");
        boolean b2;
        b2 = b1.booleanValue();
        if (!b2) 
        {
            b2 = true;
            System.out.print("x ");
        }
        if (b1 & b2) /* Line 13 */
        {
            System.out.print("y ");
        }
        System.out.println("z");
    }
}

    • Options
    • A. z
    • B. x z

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