In Java, what is the output of this program when a RuntimeException is thrown and handled, with a finally block executing? public class RTExcept { public static void throwit() { System.out.print("throwit "); throw new RuntimeException(); } public static void main(String [] args) { try { System.out.print("hello "); throwit(); } catch (Exception re) { System.out.print("caught "); } finally { System.out.print("finally "); } System.out.println("after "); } }

Introduction / Context:
This program demonstrates thrown unchecked exceptions (RuntimeException), catching with a broad Exception handler, and guaranteed execution of finally, followed by code after the try/catch/finally.

Given Data / Assumptions:

• throwit() prints "throwit " then throws new RuntimeException().
• try prints "hello " then calls throwit().
• catch (Exception) handles the RuntimeException and prints "caught ".
• finally prints "finally ".
• After the block, println prints "after " with a newline.

Concept / Approach:
Unchecked exceptions (RuntimeException) do not require a throws clause. Once thrown, control transfers to the nearest matching catch, then finally runs, then execution continues after the try/catch/finally.

Step-by-Step Solution:

Verification / Alternative check:
Change catch to catch(RuntimeException) and behavior remains the same; removing catch would still run finally and then terminate with an exception.

Why Other Options Are Wrong:
They either omit finally/after or imply compilation errors that do not occur for unchecked exceptions.

Common Pitfalls:
Thinking unchecked exceptions must be declared; forgetting that finally runs even when an exception is thrown and caught.

Final Answer:
hello throwit caught finally after