Java exceptions (try/catch structure) — what is the most accurate statement about the following code snippet?\n\nSystem.out.print("Start ");\ntry \n{\n System.out.print("Hello world");\n throw new FileNotFoundException();\n}\nSystem.out.print(" Catch Here "); // Line 7\ncatch(EOFException e) \n{\n System.out.print("End of file exception");\n}\ncatch(FileNotFoundException e) \n{\n System.out.print("File not found");\n}\n\nAssume EOFException and FileNotFoundException extend IOException.

Introduction / Context:
This item probes correctness of Java’s try/catch syntax and catch ordering. It also indirectly touches on checked exceptions. You must decide whether the presented structure is valid and, if not, why.

Given Data / Assumptions:

• A statement appears between the closing brace of the try block and the first catch.
• Two catch blocks then follow for EOFException and FileNotFoundException.
• Both exceptions are checked and extend IOException.

Concept / Approach:
In Java, a try block must be immediately followed by zero or more catch blocks and/or one finally block. No other statements are allowed between try { ... } and the first catch or finally. Placing a print statement between them breaks the grammar and causes a compile-time error, before any consideration of catch ordering.

Step-by-Step Solution:

Verification / Alternative check:
Move the “Catch Here” print either inside the try block or into a catch/finally block; compilation succeeds and the FileNotFoundException catch would execute.

Why Other Options Are Wrong:

• All printed-output options assume the code runs; it will not compile in its current form.

Common Pitfalls:
Believing you can insert arbitrary statements between try and catch; the language forbids it.

Final Answer:
The code will not compile.