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- Question
The binary equivalent of 5.375 is
Options- A. 101.101110111
- B. 101.011
- C. 101011
- D. None of above
- Correct Answer
- 101.011
- 1. What will you do to treat the constant 3.14 as a float?
Options- A. use float(3.14f)
- B. use 3.14f
- C. use f(3.14)
- D. use (f)(3.14) Discuss
- 2. What will you do to treat the constant 3.14 as a long double?
Options- A. use 3.14LD
- B. use 3.14L
- C. use 3.14DL
- D. use 3.14LF Discuss
- 3. If the binary eauivalent of 5.375 in normalised form is 0100 0000 1010 1100 0000 0000 0000 0000, what will be the output of the program (on intel machine)?
#include<stdio.h> #include<math.h> int main() { float a=5.375; char *p; int i; p = (char*)&a; for(i=0; i<=3; i++) printf("%02x\n", (unsigned char)p[i]); return 0; }
Options- A. 40 AC 00 00
- B. 04 CA 00 00
- C. 00 00 AC 40
- D. 00 00 CA 04 Discuss
- 4. Does there any function exist to convert the int or float to a string?
Options- A. Yes
- B. No Discuss
- 5. What will the function randomize() do in Turbo C under DOS?
Options- A. returns a random number.
- B. returns a random number generator in the specified range.
- C. returns a random number generator with a random value based on time.
- D. return a random number with a given seed value. Discuss
- 6. We want to round off x, a float, to an int value, The correct way to do is
Options- A. y = (int)(x + 0.5)
- B. y = int(x + 0.5)
- C. y = (int)x + 0.5
- D. y = (int)((int)x + 0.5) Discuss
- 7. Which of the following statement obtains the remainder on dividing 5.5 by 1.3?
Options- A. rem = (5.5 % 1.3)
- B. rem = modf(5.5, 1.3)
- C. rem = fmod(5.5, 1.3)
- D. Error: we can't divide Discuss
- 8. Which of the following range is a valid long double (Turbo C in 16 bit DOS OS)?
Options- A. 3.4E-4932 to 1.1E+4932
- B. 3.4E-4932 to 3.4E+4932
- C. 1.1E-4932 to 1.1E+4932
- D. 1.7E-4932 to 1.7E+4932 Discuss
- 9. A float occupies 4 bytes. If the hexadecimal equivalent of these 4 bytes are A, B, C and D, then when this float is stored in memory in which of the following order do these bytes gets stored?
Options- A. ABCD
- B. DCBA
- C. 0xABCD
- D. Depends on big endian or little endian architecture Discuss
- 10. Which statement will you add in the following program to work it correctly?
#include<stdio.h> int main() { printf("%f\n", log(36.0)); return 0; }
Options- A. #include<conio.h>
- B. #include<math.h>
- C. #include<stdlib.h>
- D. #include<dos.h> Discuss
Floating Point Issues problems
Search Results
Correct Answer: use 3.14f
Explanation:
Given 3.14 is a double constant.
To specify 3.14 as float, we have to add f to the 3.14. (i.e 3.14f)
To specify 3.14 as float, we have to add f to the 3.14. (i.e 3.14f)
Correct Answer: use 3.14L
Explanation:
Given 3.14 is a double constant.
To specify 3.14 as long double, we have to add L to the 3.14. (i.e 3.14L)
Correct Answer: 00 00 AC 40
Correct Answer: Yes
Explanation:
1. itoa() converts an integer to a string.
2. ltoa() converts a long to a string.
3. ultoa() converts an unsigned long to a string.
4. sprintf() sends formatted output to a string, so it can be used to convert any type of values to string type.
2. ltoa() converts a long to a string.
3. ultoa() converts an unsigned long to a string.
4. sprintf() sends formatted output to a string, so it can be used to convert any type of values to string type.
#include<stdio.h>
#include<stdlib.h>
int main(void)
{
int num1 = 12345;
float num2 = 5.12;
char str1[20];
char str2[20];
itoa(num1, str1, 10); /* 10 radix value */
printf("integer = %d string = %s \n", num1, str1);
sprintf(str2, "%f", num2);
printf("float = %f string = %s", num2, str2);
return 0;
}
// Output:
// integer = 12345 string = 12345
// float = 5.120000 string = 5.120000
Correct Answer: returns a random number generator with a random value based on time.
Explanation:
The randomize() function initializes the random number generator with a random value based on time. You can try the sample program given below in Turbo-C, it may not work as expected in other compilers.
/* Prints a random number in the range 0 to 99 */
#include <stdlib.h>
#include <stdio.h>
#include <time.h>
int main(void)
{
randomize();
printf("Random number in the 0-99 range: %d\n", random (100));
return 0;
}
Correct Answer: y = (int)(x + 0.5)
Explanation:
Rounding off a value means replacing it by a nearest value that is approximately equal or smaller or greater to the given number.
y = (int)(x + 0.5); here x is any float value. To roundoff, we have to typecast the value of x by using (int)
Example:
#include <stdio.h>
int main ()
{
float x = 3.6;
int y = (int)(x + 0.5);
printf ("Result = %d\n", y );
return 0;
}
Output:
Result = 4.
Correct Answer: rem = fmod(5.5, 1.3)
Explanation:
fmod(x,y) - Calculates x modulo y, the remainder of x/y.
This function is the same as the modulus operator. But fmod() performs floating point divisions.
This function is the same as the modulus operator. But fmod() performs floating point divisions.
Example:
#include <stdio.h>
#include <math.h>
int main ()
{
printf ("fmod of 5.5 by 1.3 is %lf\n", fmod (5.5, 1.3) );
return 0;
}
Output:
fmod of 5.5 by 1.3 is 0.300000
Correct Answer: 3.4E-4932 to 1.1E+4932
Explanation:
The range of long double is 3.4E-4932 to 1.1E+4932
Correct Answer: Depends on big endian or little endian architecture
Correct Answer: #include<math.h>
Explanation:
math.h is a header file in the standard library of C programming language designed for basic mathematical operations.
Declaration syntax: double log(double);
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