What will be the output of the program? #include int main() { float *p; printf("%d ", sizeof(p)); return 0; }

Question

What will be the output of the program? #include<stdio.h>
int main()
{
    float *p;
    printf("%d
", sizeof(p));
    return 0;
}

Accepted Answer

sizeof(x) returns the size of x in bytes.
float *p is a pointer to a float.

In 16 bit compiler, the pointer size is always 2 bytes.
In 32 bit compiler, the pointer size is always 4 byt…

What will be the output of the program? #include<stdio.h> int main() { float *p; printf("%d\n", sizeof(p)); return 0; }