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- Question
In the following program where is the variable a getting defined and where it is getting declared?
#include<stdio.h> int main() { extern int a; printf("%d\n", a); return 0; } int a=20;
Options- A. extern int a is declaration, int a = 20 is the definition
- B. int a = 20 is declaration, extern int a is the definition
- C. int a = 20 is definition, a is not defined
- D. a is declared, a is not defined
- Correct Answer
- extern int a is declaration, int a = 20 is the definition
Explanation- During declaration we tell the datatype of the Variable.- During definition the value is initialized.
More questions
- 1. Bitwise can be used to reverse a sign of a number.
Options- A. Yes
- B. No Discuss
Correct Answer: No
- 2. Is it necessary that in a function which accepts variable argument list there should be at least be one fixed argument?
Options- A. Yes
- B. No Discuss
Correct Answer: Yes
- 3. Bitwise can be used to generate a random number.
Options- A. Yes
- B. No Discuss
Correct Answer: No
- 4. A function that receives variable number of arguments should use va_arg() to extract the last argument from the variable argument list.
Options- A. True
- B. False Discuss
Correct Answer: False
- 5. Bitwise & can be used to check if more than one bit in a number is on.
Options- A. True
- B. False Discuss
Correct Answer: True
- 6. The preprocessor can trap simple errors like missing declarations, nested comments or mismatch of braces.
Options- A. True
- B. False Discuss
Correct Answer: False
Explanation:
False, the preprocessor cannot trap the errors, it only replaces the macro with the given expression. But the compiler will detect errors.- 7. It is necessary that a header files should have a .h extension?
Options- A. Yes
- B. No Discuss
Correct Answer: No
Explanation:
No, the header files have any kind of extension.- 8. Bitwise | can be used to set multiple bits in number.
Options- A. Yes
- B. No Discuss
Correct Answer: Yes
- 9. Bitwise & can be used to check if a bit in number is set or not.
Options- A. True
- B. False Discuss
Correct Answer: True
- 10. A pointer union CANNOT be created
Options- A. Yes
- B. No Discuss
Correct Answer: No
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