What is the output of the program? #include int main() { extern int a; printf("%d\n", a); return 0; } int a=20;

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What is the output of the program? #include<stdio.h> int main() { extern int a; printf("%d\n", a); return 0; } int a=20;

20
0
Garbage Value
Error

Correct Answer: 20

Explanation:

extern int a; indicates that the variable a is defined elsewhere, usually in a separate source code module.

printf("%d\n", a); it prints the value of local variable int a = 20. Because, whenever there is a conflict between local variable and global variable, local variable gets the highest priority. So it prints 20.

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