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What is the output of the program given below? #include int main() { enum status { pass, fail, atkt}; enum status stud1, stud2, stud3; stud1 = pass; stud2 = atkt; stud3 = fail; printf("%d, %d, %d\n", stud1, stud2, stud3); return 0; }

Q: What is the output of the program given below? #include int main() { enum status { pass, fail, atkt}; enum status stud1, stud2, stud3; stud1 = pass; stud2 = atkt; stud3 = fail; printf("%d, %d, %d\n", stud1, stud2, st…

enum takes the format like {0,1,2..) so pass=0, fail=1, atkt=2 stud1 = pass (value is 0) stud2 = atkt (value is 2) stud3 = fail (value is 1) Hence it prints 0, 2, 1

0, 1, 2
1, 2, 3
0, 2, 1
1, 3, 2

Correct Answer: 0, 2, 1

Explanation:

enum takes the format like {0,1,2..) so pass=0, fail=1, atkt=2

stud1 = pass (value is 0)

stud2 = atkt (value is 2)

stud3 = fail (value is 1)

Hence it prints 0, 2, 1

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