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Exam Questions Papers
Consider the probability density f(x) = ae-b|x| where x is a random variable whose allowable values range from x = - ∞ to x = + ∞. P(1 ≤ x ≤ 2)
(e-b - e-2b)
Correct Answer:
Explanation:
P(
x
) =
ae
-b|x|
d
x
to get
apply
ae
bx
dx
+
ae
-bx
d
x
,
we get
=
.
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