Curioustab
Aptitude
General Knowledge
Verbal Reasoning
Computer Science
Interview
Aptitude
General Knowledge
Verbal Reasoning
Computer Science
Interview
Home
»
Electronics and Communication Engineering
»
Exam Questions Papers
Consider the signal flow graph shown in figure below. The gain is :
Correct Answer:
Explanation:
P
1
=
abcd
L
1
=
be
, L
2
=
cf
, L
3
=
dg
Δ
1
= 1
.
← Previous Question
Next Question→
More Questions from
Exam Questions Papers
In the following non planar graph number of independent loop equations are
The amplifier circuit shown below uses a silicon transistor. The capacitors Cc and CE can be assumed to be short at signal frequency and the effect of output resistance r0 can be ignored. If CE is disconnected from the circuit, which one of the following statements is TRUE?
Consider the amplitude modulated (AM) signal Ac cos ωct + 2 cos ωmt cos ωct For demodulating the signal using envelope detector, the minimum value of Ac should be
A unity-feedback control system has the open loop transfer function . If the input system is a unit ramp, the steady state error will be
A certain 8 bit uniform quantization PCM system can accommodate a signal ranging from - 1 V to + V. The rms value of the signal is V . The signal to quantization noise ratio is:
In a semiconductor material. The hole concentration is found to be 2 x 2.5 x 1015 cm-3. If mobility of carriers is 0.13 m2/ v-s. Then find the current density if electric field intensity is 3.62 x 10-19
The analog signal given below is sampled at 1200 samples per second. m(t) = 2 sin 120 pt + 3 sin 240 pt + 4 sin 360 pt + 5 sin 480 pt + 6 sin 600 pt + 7 sin 720 pt. The folding (maximum) frequency is __________ .
A rectangular waveguide, in dominant TE mode, has dimensions 10 cm x 15 cm. The cut off frequency is
A noiseless 3 KHz channel can transmit binary at the rate __________ .
Radiation resistance of an antenna is 54 Ω and loss resistance is 6 Ω. If antenna has power gain of 10, then directivity is:
Discussion & Comments
No comments yet. Be the first to comment!
Name:
Comment:
Post Comment
Join Discussion
Discussion & Comments