In a semiconductor material. The hole concentration is found to be 2 x 2.5 x 1015 cm-3. If mobility of carriers is 0.13 m2/ v-s. Then find the current density if electric field intensity is 3.62 x 10-19

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Accepted Answer

Current density J = σE

Where σ = conductivity

Given -> μ = 0.13 m²/v-s = 0.13 x 10⁴ cm²/V sec

P = 2.25 x 10¹⁵/cm³

We have, ∴ n_i = 1.5 x 10¹⁰

Also n.p. =

∴ n = /p

= (1.6 x 10^-19 x 0.13 x 10⁴ x 2.25 x 10¹⁵) x

= (0.468) (4.5 x 10¹⁵)

σ = 2.106 x 10¹⁵ μ/cm

J = σE

∴ Current density = 2.106 x 10¹⁵ x 3.620 x 10^-19

= 7.6237 x 10^-4 A/m².

In a semiconductor material. The hole concentration is found to be 2 x 2.5 x 1015 cm-3. If mobility of carriers is 0.13 m2/ v-s. Then find the current density if electric field intensity is 3.62 x 10-19

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