A load of 500 kg was lifted through a distance of 13 cm. by an effort of 25 kg which moved through a distance of 650 cm. The efficiency of the lifting machine is
Options
A. 50%
B. 40%
C. 55%
D. 30%.
Correct Answer
40%
Applied Mechanics problems
Search Results
1. The locus of the instantaneous centre of a moving rigid body, is
3. The equation of motion of a particle starting from rest along a straight line is x = t3 - 3t2 + 5. The ratio of the accelerations after 5 sec and 3 sec will be
8. Parallelogram Law of Forces states, "if two forces acting simultaneously on a particle be represented in magnitude and direction by two adjacent sides of a parallelogram, their resultant may be represented in magnitude and direction by
Options
A. its longer side"
B. its shorter side"
C. the diagonal of the parallelogram which does not pass through the point of intersection of the forces"
D. the diagonal of the parallelogram which passes through the point of intersection of the forces"
Siddhi Rajendra ghuge Mechanical advantage (MA) = Load (W)/Effort (P).
MA = W/P = 500/25 = 20.
Velocity ratio (VR) = (Distance moved by the effort (Y))/(Distance moved by the load (X)).
VR = Y/X = 650/13 = 50.
Efficiency = MA/VR = 20/50 = 40%.
40 % is the correct ans
Mechanical advantage (MA) = Load (W)/Effort (P). MA = W/P = 500/25 = 20. Velocity ratio (VR) = (Distance moved by the effort (Y))/(Distance moved by the load (X)). VR = Y/X = 650/13 = 50. Efficiency = MA/VR = 20/50 = 40%. 40 % is the correct ans