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  • Question
  • A load of 500 kg was lifted through a distance of 13 cm. by an effort of 25 kg which moved through a distance of 650 cm. The efficiency of the lifting machine is


  • Options
  • A. 50%
  • B. 40%
  • C. 55%
  • D. 30%.

  • Correct Answer
  • 40% 


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    Comments

    Avatar
    Siddhi Rajendra ghuge
    Mechanical advantage (MA) = Load (W)/Effort (P). MA = W/P = 500/25 = 20. Velocity ratio (VR) = (Distance moved by the effort (Y))/(Distance moved by the load (X)). VR = Y/X = 650/13 = 50. Efficiency = MA/VR = 20/50 = 40%. 40 % is the correct ans


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