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  • Question
  • In a cricket match, five batsmen A, B, C, D and E scored an average of 36 runs. D Scored 5 more than E; E scored 8 fewer than A; B scored as many as D and E combined; and B and C scored 107 between them. How many runs did E score?


  • Options
  • A. 62
  • B. 45
  • C. 28
  • D. 20

  • Correct Answer
  • 20 

    Explanation
    Total runs scored = (36 x 5) = 180.

    Let the runs scored by E be x.

    Then, runs scored by D = x + 5; runs scored by A = x + 8;

    runs scored by B = x + x + 5 = 2x + 5;

    runs scored by C = (107 - B) = 107 - (2x + 5) = 102 - 2x.

    So, total runs = (x + 8) + (2x + 5) + (102 - 2x) + (x + 5) + x = 3x + 120.

    Therefore 3x + 120 =180 ⟺ 3X = 60 ⟺ x = 20.


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