Linked ages with time shifts: Solve present ages from future and past relations. A is three times as old as B. Four years ago, C was twice as old as A was then. In four years' time, A will be 31. Find the present ages of B and C. Choose the correct ordered pair.

Difficulty: Medium

Correct Answer: 9, 50

Explanation:


Compute A first
A in 4 years = 31 ⇒ A now = 31 − 4 = 27.


Find B
A = 3B ⇒ 27 = 3B ⇒ B = 9.


Find C
Four years ago: A was 23 ⇒ C was twice that: 2 × 23 = 46. So C now = 46 + 4 = 50.


Check
Relations satisfied: A=27, B=9, C=50 ✔

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