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A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C?

Correct Answer: 9, 50

Explanation:

We have : A = 3B ...(i) and


C - 4 = 2 (A - 4) ...(ii)


Also, A + 4 = 31 or A= 31-4 = 27.


Putting A = 27 in (i), we get: B = 9.


Putting A = 27 in (ii), we get C = 50.


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