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- Question
A dishonest milkman professes to sell his milk at cost price but he mixes it with water and thereby gains 25%. The percentage of water in the mixture is:
Options- A. 4%
- B. 6¼%
- C. 20%
- D. 25%
- Correct Answer
- 20%
ExplanationLet C.P. of 1 litre milk be Re. 1Then, S.P. of 1 litre of mixture = Re. 1, Gain = 25%.
C.P. of 1 litre mixture = Re. ❨ 100 x 1 ❩ = 4 125 5 By the rule of alligation, we have:
C.P. of 1 litre of milk C.P. of 1 litre of water Re. 1 Mean Price
Re. 4 5 0 4 5 1 5 ∴ Ratio of milk to water = 4 : 1 = 4 : 1. 5 5 Hence, percentage of water in the mixture = ❨ 1 x 100 ❩% = 20%. 5
More questions
- 1. If m men working m h per day, can do m units of work in m days, then n men working n h per day would be able to complete how units of work in days?
Options- A. n3/m2
- B. m3/n2
- C. m4/n2
- D. n4/m3 Discuss
Correct Answer: n3/m2
Explanation:
Let the required number of units of work = k
According to the formula,
W1= m and W2 = k
M1T1D1W2 = M2T2D2W1
? m x m x m x k = n x n x n x m
? x= (m x n3) / m3 = n3/m2- 2. The average age of two boys and their father is greater then average age of those two boys and their mother by 3 yr. The average age of the four is 19 yr. If the average age of the two boys be 5 1/ 2, then find the age of the father and mother.
Options- A. 37 yr and 28 yr
- B. 47 yr and 38 yr
- C. 50 yr and 41 yr
- D. 35 yr and 32 yr Discuss
Correct Answer: 37 yr and 28 yr
Explanation:
Let the ages of mother, father and boys be M, F, B1 and B2, respectively.
The total age of four member
= 19 x 4
= 76 yr.
Given (B1 + B1)/2 = 11/2
? B1 + B2 = 11
M + F + B1 + B2 = 76 - 11
? M + F = 65 .......(i)
According to the question,
(B1 + B2 + F) / 3 = (B1 + B2 + M) / 3 + 3
? B1 + B2 + F) = B1 + B2 + M + 9
? F = M + 9
? F - M = 9 ............. (ii)
From Eqs (i) and (ii), we get
F = 37 yr and M = 28 yr- 3. 387 x 387 + 114 x 114 + 2 x 387 x 114 =?
Options- A. 250001
- B. 251001
- C. 260101
- D. 261001 Discuss
Correct Answer: 251001
Explanation:
Given expression = a2+b2+2ab = (a+b)2
where a = 387 and b = 114
= (387 + 114 )2
= (501)2
=(500 +1 )2
=(500)2 + (1)2+ 2 x 500 x 1
= 250000 + 1 +1000 = 251001.- 4. 3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day should 4 pumps work in order to empty the tank in 1 day?
Options- A. 10
- B. 12
- C. 8
- D. 15 Discuss
Correct Answer: 12
Explanation:
3 pumps, can empty a tank in 2 days by working 8 hours a day.
1 pumps, can empty a tank in 2 days by working 8 x 3 hours a day.
1 pumps, can empty a tank in 1 days by working 8 x 3 x 2hours a day.
4 pumps, can empty a tank in 1 days by working 8 x 3 x 2 / 4 hours a day.
4 pumps, can empty a tank in 1 days by working 2 x 3 x 2 hours a day.
4 pumps, can empty a tank in 1 days by working 12 hours a day.- 5. In how many different ways can the letters of word JUDGE be arranged so that the vowels always come together?
Options- A. 48
- B. 24
- C. 120
- D. 60 Discuss
Correct Answer: 48
Explanation:
Total number of letters = 5
Number of vowels = 2.
If we consider both vowel as a one letter then,
Required number = 4! 2! = 48.- 6. A sum of money amounts to Rs. 850 in 3 years and Rs. 925 in 4 year. The sum is?
Options- A. Rs. 600
- B. Rs. 575
- C. Rs. 625
- D. Data inadequate Discuss
Correct Answer: Rs. 625
Explanation:
S.I for 1 year = Rs. (925 - 850) = Rs. 75
S.I for 3 year = Rs. (75 x 3) = Rs. 225
? Sum = Rs. (850 - 225) = Rs. 625
- 7. If the diameters of a circle is increased by 100% . Its area is increased by?
Options- A. 100%
- B. 200%
- C. 300%
- D. 400% Discuss
Correct Answer: 300%
Explanation:
Original area = ?(d/2)2
= (?d2) / 4
New area = ?(2d/2)2
= ?d2
Increase in area = (?d2 - ?d2/4)
= 3?d2/4
? Required increase percent
= [(3?d2)/4 x 4/(?d2) x 100]%
= 300%- 8. The traffic lights at three different road crossings changes after every 48 sec., 72 sec. and 108 sec. respectively. If they all change simultaneously at 8 : 20 : 00 hrs, then they will again change simultaneously at?
Options- A. 8 : 27 : 12 hrs.
- B. 8 : 27 : 24 hrs.
- C. 8 : 27 : 36 hrs.
- D. 8 : 27 : 48 hrs. Discuss
Correct Answer: 8 : 27 : 12 hrs.
Explanation:
Interval of changes = (L . C . M of 48, 72, 108) sec. = 432 sec.
So, the lights will simultaneously changes after every 432 seconds i,e 7 min. 12 sec.
So, the next simultaneously changes will take place at 8 : 27 : 12 hrs.- 9. Average weight of 19 men is 74 kg and the average weight of 38 women is 63 kg. What is the average weight(rounded off to the nearest integer) of all the men and the women together.
Options- A. 59 kg
- B. 65 kg
- C. 69 kg
- D. 67 kg Discuss
Correct Answer: 67 kg
Explanation:
Here n1 = 19, a1 = 74, n2 = 38, a1 = 63
Total average weight = (n1a1 + n2 a2) / (n1 + n2)
= [(19) (74) + (38) (63)] / (19 + 38)
= 3800/57 ? 67 kg- 10. Find the highest common factor of 36 and 84.
Options- A. 4
- B. 6
- C. 12
- D. 18 Discuss
Correct Answer: 12
Explanation:
36 = 2 2 x 3 284 = 22 x 3 x 7
∴ H.C.F. = 22 x 3 = 12.
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