Explanation: The requirement of having to allocate 500 hosts on each subnet can be achieved by the following: 2^9 = 512. So deducting the broadcast and network address we have 510 possible hosts on each subnet. We used 9 bits to allocate the hosts, this leaves us 7 bits for possible subnets. Those 7 bits in binary is 1111 1110 or 254 in decimal.
The IEEE 802.11b standard provides three non-overlapping channels.
A transmission to the MAC address ff : ff : ff : ff : ff : ff is a broadcast transmission to all stations.
After the expiration of the backoff algorithm , all hosts have equal priority.
To use VLSM, the routing protocols in use possess the capability to transmit subnet mask information.
The typical banner is a message of the day (MOTD) and is set by using the global configuration mode command banner motd.
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