At what time between 2 and 3 O'clock, the hands of a clock coincide ?

Since, in one hour, two hands of a clock coincide only once, so, there will be value.
Required time  $T = \frac{2}{11}H\times 30 + Ao$ minutes past H.
Here H - initial position of hour hand = 2 (since 2 O'clock)
A° = Required angle = 0° (Since it coincides)

$T = \frac{2}{11}2\times 30 + 0o$ minutes past 2 

=> $1\frac{10}{11}$ minutes past 2