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  • Question
  • Two metallic plate of equal thickness and coefficient thermal conductivity K1 and K2 put together face to face. A common plate is constructed. What is equivalent K?


  • Options
  • A. K1k2/k1+k2
  • B. 2k1k2/k1+k2
  • C. K1+k2/k1k2
  • D. None

  • Correct Answer
  • 2k1k2/k1+k2 

    Explanation

    We know that,

     

    The equivalent K =   L 1   +   L 2 L 1 K 1 + L 2 K 2

     

    where L1 & L2 are plate1 & Plate2 thicknesses, K1 & K2 are coefficient thermal conductivity of plate1 & Plate2 respectively.

     

    But here L1 = L2 = L (say)

     

    Then K = L+L/(L/K1 + L/K2)  =   2 K 1 K 2 K 1 + K 2

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