One day work of Raghu and Sam together = 1/12 + 1/15 = 9/60 = 3/20
Aru efficiency = 2/3 of (Raghu + Sam)
Number of days required for Aru to do thw work alone = 3/2 x 20/3 = 10 days.
The mother completes the job in x hours.
So, the daughter will take 2x hours to complete the same job.
In an hour, the mother will complete 1/x of the total job.
In an hour, the daughter will complete 1/2x of the total job.
So, if the mother and daughter work together, in an hour they will complete 1/x + 1/2x of the job.
i.e., in an hour they will complete 3/2x of the job.
The question states that they complete the entire task in 6 hours if they work together.
i.e., they complete 1/6 th of the task in an hour.
Equating the two information, we get 3/2x = 1/6
By solving for x, we get 2x = 18 or x = 9.
The mother takes 9 hours to complete the job.
Given 2000 ---- 54 days
The provisions for 2000 men for 39 days can be completed by 'm' men for only 20 days.
i.e, 2000 ----- 39 days == m ---- 20 days
=> m x 20 = 2000 x 39
m = 3900
So total men for 20 days is 3900
=> 2000 old and 1900 new reinforcement.
Hence, reinforcement = 1900.
work done=total number of person x number of days;
half of work done = 140 x 66;
For half of remaining work 25 extra men are added.
Therefore, total men for half work remaining = 140 + 25 = 165;
Let 2nd half work will be completed in K days;
140 x 66 = 165 x K
K = 122;
Hence, extra days => 122-120 = 2days.
From the given data,
12 children 16 days work,
One child?s one day work = 1/192.
8 adults 12 days work,
One adult?s one day?s work = 1/96.
Work done in 3 days = ((1/96) x 16 x 3) = 1/2
Remaining work = 1 ? 1/2 = 1/2
(6 adults+ 4 children)?s 1 day?s work = 6/96 + 4/192 = 1/12
1/12 work is done by them in 1 day.
1/2 work is done by them in 12 x (1/2) = 6 days.
We know that,
Here M1 = 1, D1 = 6 min, W1 = 1 and M2 = M, D2 = 90 min, W2 = 1845
=> M = 123
B's 8 days work=(1/12) x 8 = 2/3
Reaining work= 1/3
Now, 1/15 work is done by A in 1 day
Therefore, 1/3 work is done by A in 15 x (1/3) = 5 days
Time taken by 8th tap = 2 x 2 x 2= 8 hours
Time taken by 12th tap = 2x (1/2) x (1/2) = 1/2 hour
Ratio of time taken by 8th tap and 12th tap = 8 : 1/2 =16:1
Therefore, Ratio of efficiencies of 8th tap and 12th tap =1:16
Work done by Shyam and Rahim in 8 days = 8/32 = 1/4
Remaining work to be done by Shyam and Ram = 1 - 1/4 = 3/4
Given efficieny of Ram is half of Rahim i.e, as Rahim can do the work in 48 days, Ram can do the work in 24 days.
One day work of Ram and Shyam = (1/32 - 1/48) + 1/24 = 5/96
Hence, the total work can be done by Shyam and Ram together in 96/5 days.
Therefore, remaining work 3/4 can be done by them in 3/4 x 96/5 = 72/5 = 14.4 days.
Here given soldier shots 7 shots in 12 min
=> 1 shot doen't take any time in 12 min
=> Only 6 shots take 12 min
12 min ------ 6 shots
90 min ------ ? shots
=> 90 x (6/12) = 45
Therefore, total shots fired in 90 minutes = 45 + 1 = 46 shots.
Let the total women in the group be 'W'
Then according to the given data,
W x 20 = (W-12) x 32
=> W = 32
Therefore, the total number of women in the group = 32
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