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- Question
A, B and C can complete a piece of work in 24,6 and 12 days respectively.Working together, they will complete the same work in:
Options- A. 1/24 days
- B. 7/24 days
- C. 24/7 days
- D. 4 days
- Correct Answer
- 24/7 days
Explanation(A+B+C)'s 1 day's work = (1/24 + 1/6 + 1/12) = 7/24
so, A,B and C together will complete the work in 24/7 days.
- 1. There are three boats B1, B2 and B3 working together they carry 60 people in each trip. One day an early morning B1 carried 50 people in few trips alone. When it stopped carrying the passengers B2 and B3 started carrying the people together. It took a total of 10 trips to carry 300 people by B1, B2 and B3. It is known that each day on an average 300 people cross the river using only one of the 3 boats B1, B2 and B3. How many trips it would take to B1, to carry 150 passengers alone?
Options- A. 15
- B. 30
- C. 25
- D. 10 Discuss
- 2. A does half as much work as Band C does half as much work as A and B together. If C alone can finish the work in 40 days, then together ,all will finish the work in ?
Options- A. 17 + 4/7 days
- B. 13 + 1/3 days
- C. 15 + 3/2 days
- D. 16 days Discuss
- 3. Two pipes A and B can fill a tank in 24 hours and 1717 hours respectively. Harihar opened the pipes A and B to fill an empty tank and some times later he closed the taps A and B , when the tank was supposed to be full. After that it was found that the tank was emptied in 2.5 hours because an outlet pipe "C" connected to the tank was open from the beginning. If Harihar closed the pipe C instead of closing pipes A and B the remaining tank would have been filled in :
Options- A. 2 hours
- B. 8 hours
- C. 6 hours
- D. 4 hours Discuss
- 4. A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days ?
Options- A. 9 days
- B. 11 days
- C. 13 days
- D. 15 days Discuss
- 5. A and B can do a work in 4 hours and 12 hours respectively. A starts the work at 6 AM and they work alternately for one hour each. When will the work be completed?
Options- A. 4 days
- B. 5 days
- C. 6 days
- D. 7 days Discuss
- 6. 16 women can do a piece of work in 10 days while 15 men can do the same work in 12 days. All men and all women work alternately starting with all men, then find the time taken by them to complete the whole work?
Options- A. 10 5/2 days
- B. 11 days
- C. 11 2/5 days
- D. 12 1/2 days Discuss
- 7. When A, B and C are deployed for a task , A and B together do 70% of the work and B and C together do 50% of the work. who is most efficient?
Options- A. A
- B. B
- C. C
- D. can't be determined Discuss
- 8. 4 men can repair a road in 7 hours. How many men are required to repair the road in 2 hours ?
Options- A. 17 men
- B. 14 men
- C. 13 men
- D. 16 men Discuss
- 9. A and B together can do a piece of work in 40 days. A having worked for 20 days, B finishes the remaining work alone in 60 days. In How many days shall B finish the whole work alone?
Options- A. 60
- B. 70
- C. 80
- D. 90 Discuss
- 10. If 2 men and 3 women can do a piece of work in 8 days and 3 men and 2 women in 7 days. In how many days can the work be done by 5 men and 4 women working together?
Options- A. 3 days
- B. 6 days
- C. 4 days
- D. 2 days Discuss
Time and Work problems
Search Results
Correct Answer: 15
Explanation:
Combined efficiency of all the three boats = 60 passenger/trip
Now, consider option(a)
15 trips and 150 passengers means efficiency of B1 = 10 passenger/trip
which means in carrying 50 passengers B1 must has taken 5 trips. So the rest trips equal to 5 (10-5 = 5) in which B2 and B3 together carried remaining 250 (300 - 50 = 250) Passengers.
Therefore the efficiency of B2 and B3 = 250/5 = 50 passenger/trip
Since, the combined efficiency of B1, B2 and B3 is 60. Which is same as given in the first statement hence option(a) is correct.
Correct Answer: 13 + 1/3 days
Explanation:
C alone can finish the work in 40 days.
As given C does half as much work as A and B together
=> (A + B) can do it in 20 days
(A + B)s 1 days wok = 1/20.
A's 1 days work : B's 1 days Work = 1/2 : 1 = 1:2(given)
A's 1 day?s work = (1/20) x (1/3) = (1/60) [Divide 1/20 in the raio 1:2]
B's 1 days work = (1/20) x (2/3) = 1/30
(A+B+C)'s 1 day's work = (1/60) + (1/30) + (1/40) = 9/120 = 3/40
All the three together will finish it in 40/3 = 13 and 1/3 days.
Correct Answer: 8 hours
Explanation:
Efficiency of Inlet pipe A = 4.16%
Efficiency of Inlet pipe B = 5.83%
Therefore, Efficiency of A and B together = 100 %
Now, if the efficiency of outlet pipe be x% then in 10 hours the capacity of tank which will be filled = 10 * (10 - x)
Now, since this amount of water is being emptied by 'C' at x% per hour, then
=> x = 8
Therefore, in 10 hours 20% tank is filled only. Hence, the remaining 80% of the capacity will be filled by pipes A and B in 80/10 = 8 hours
Correct Answer: 13 days
Explanation:
Ratio of times taken by A and B = 100 : 130 = 10 : 13.
Suppose B takes x days to do the work.
Then, 10 : 13 :: 23 : x => x = ( 23 x 13/10 ) => x = 299 /10.
A's 1 day's work = 1/23 ;
B's 1 day's work = 10/299 .
(A + B)'s 1 day's work = ( 1/23 + 10/299 ) = 23/299 = 113 .
Therefore, A and B together can complete the work in 13 days.
Correct Answer: 6 days
Explanation:
Work donee by A and B in the first two hours, working alternatively = First hour A + Second hour B = (1/4) + (1/12) = 1/3.
Thus, the total time required to complete the work = 2 (3) = 6 days
Correct Answer: 10 5/2 days
Explanation:
Let efficiency of every man and every woman be 'm' unit/day and 'w' unit/day respectively
15×12×m = 10×16×w
? m/w = 8/9
Total work = 15 × 12 × 9 = 1620 units
In 2 days, total work done = 15 x 9 + 16 x 8 = 263 units
So, in 10 days work done will be = 263 × 5 = 1315 units
Remaining work will be done in = (1620-1315)/(15×8) = 5/2 days
Total days = 10 5/2 days.
Correct Answer: A
Explanation:
A + B= 70%
B + C =50%
=> B= 20% A= 50% and C=30%
Hence A is most efficient
Correct Answer: 14 men
Explanation:
M x T / W = Constant
where, M= Men (no. of men)
T= Time taken
W= Work load
So, here we apply
M1 x T1/ W1 = M2 x T2 / W2
Given that, M1 = 4 men, T1 = 7 hours ; T2 = 2 hours, we have to find M2 =?
Note that here, W1 = W2 = 1 road, ie. equal work load.
Clearly, substituting in the above equation we get, M2 = 14 men.
Correct Answer: 80
Explanation:
Let A's 1 day's work=x and B's 1 day's work=y
Then x+y = 1/40 and 20x+60y=1
Solving these two equations , we get : x= 1/80 and y= 1/80
Therefore B's 1 day work = 1/80
Hence,B alone shall finish the whole work in 80 days
Correct Answer: 4 days
Explanation:
From the given data,
=> (2 M + 3W) 8 = (3M + 2W)7
=> 16M + 24W = 21M + 14 W
=> 10W = 5M
=> 2W = M
=> 14W × ? = 7W × 8
? = 4 days
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