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- Question
If two letters are taken at random from the word HOME, what is the probability that none of the letters would be vowels?
Options- A. 1/6
- B. 1/2
- C. 1/3
- D. 1/4
- Correct Answer
- 1/6
ExplanationP(first letter is not vowel) =
P(second letter is not vowel) =
So, probability that none of letters would be vowels is =
- 1. 8 couples (husband and wife) attend a dance show "Nach Baliye' in a popular TV channel ; A lucky draw in which 4 persons picked up for a prize is held, then the probability that there is atleast one couple will be selected is :
Options- A. 8/39
- B. 15/39
- C. 12/13
- D. None of these Discuss
- 2. One card is drawn at random from a pack of 52 cards. What is the probability that the card drawn is a face card (Jack, Queen and King only)?
Options- A. 3/13
- B. 1/13
- C. 3/52
- D. 9/52 Discuss
- 3. Three unbiased coins are tossed.What is the probability of getting at least 2 heads?
Options- A. 1/4
- B. 1/2
- C. 3/4
- D. 1/3 Discuss
- 4. A bag contains 6 black and 8 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?
Options- A. 3/7
- B. 4/7
- C. 1/8
- D. 3/4 Discuss
- 5. Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is:
Options- A. 3/20
- B. 29/34
- C. 47/100
- D. 13/102 Discuss
- 6. In a class, 30% of the students offered English, 20% offered Hindi and 10% offered both. If a student is selected at random, what is the probability that he. has offered English or Hindi ?
Options- A. 1/2
- B. 3/4
- C. 4/5
- D. 2/5 Discuss
- 7. A bag contains 2 red Roses, 4 yellow Roses and 6 pink Roses. Two roses are drawn at random. What is the probability that they are not of same color?
Options- A. 1/6
- B. 2/3
- C. 14/33
- D. 5/6 Discuss
- 8. Three unbiased coins are tossed. What is the probability of getting at most two heads?
Options- A. 3/4
- B. 7/8
- C. 1/2
- D. 1/4 Discuss
- 9. A bag contains 50 tickets numbered 1,2,3,4......50 of which five are drawn at random and arranged in ascending order of magnitude.Find the probability that third drawn ticket is equal to 30.
Options- A. 551/15134
- B. 1/2
- C. 552/15379
- D. 1/9 Discuss
- 10. A speaks truth in 75% of cases and B in 80% of cases. In what percentage of cases are they likely to contradict each other, narrating the same incident
Options- A. 30/100
- B. 35/100
- C. 45/100
- D. 50/100 Discuss
Probability problems
Search Results
Correct Answer: 15/39
Explanation:
P( selecting atleast one couple) = 1 - P(selecting none of the couples for the prize)
=
Correct Answer: 3/13
Explanation:
Clearly, there are 52 cards, out of which there are 12 face cards.
P (getting a face card) = 12/52=3/13.
Correct Answer: 1/2
Explanation:
Here S= {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}.
Let E = event of getting at least two heads = {THH, HTH, HHT, HHH}.
P(E) = n(E) / n(S)
= 4/8= 1/2
Correct Answer: 4/7
Explanation:
Let number of balls = (6 + 8) = 14.
Number of white balls = 8.
P (drawing a white ball) = 8 /14 = 4/7.
Correct Answer: 13/102
Explanation:
Let S be the sample space.
Then, n(S) = =(52 x 51)/(2 x 1) = 1326.
Let E = event of getting 1 spade and 1 heart.
n(E)= number of ways of choosing 1 spade out of 13 and 1 heart out of 13 = = 169.
P(E) = n(E)/n(S) = 169/1326 = 13/102.
Correct Answer: 2/5
Correct Answer: 2/3
Explanation:
Possible outcomes = (RY, YP, PR)
2C1 4C1 + 4C1 6C1 + 6C1 2C1
Required probability = (2C1 4C1 + 4C1 6C1 + 6C1 2C1)/(12C2)
= 8 + 24 + 12/66
= 44/66
= 2/3.
Correct Answer: 7/8
Explanation:
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
P(E) =n(E)/n(S)=7/8.
Correct Answer: 551/15134
Explanation:
Total number of elementary events =
Given,third ticket =30
=> first and second should come from tickets numbered 1 to 29 = ways and remaining two in ways.
Therfore,favourable number of events =
Hence,required probability = =551 / 15134
Correct Answer: 35/100
Explanation:
Let A = Event that A speaks the truth
B = Event that B speaks the truth
Then P(A) = 75/100 = 3/4
P(B) = 80/100 = 4/5
P(A-lie) = = 1/4
P(B-lie) = = 1/5
Now, A and B contradict each other =[A lies and B true] or [B true and B lies]
= P(A).P(B-lie) + P(A-lie).P(B)
=
= = 35%
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