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A bag contains 2 red Roses, 4 yellow Roses and 6 pink Roses. Two roses are drawn at random. What is the probability that they are not of same color?

Correct Answer: 2/3

Explanation:

Possible outcomes = (RY, YP, PR)


2C1 4C1 + 4C1 6C1 + 6C1 2C1


Required probability = (2C1 4C1 + 4C1 6C1 + 6C1 2C1)/(12C2)


= 8 + 24 + 12/66


= 44/66


= 2/3.


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