Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three apply for the same house is :

Q: Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three apply for the same house is :

One person can select one house out of 3= 3 C 1 ways =3. Hence, three persons can select one house out of 3 in 3 x 3 x 3 =9. Therefore, probability that all thre apply for the same house is 1/9

2/9
1/9
8/9
7/9

Correct Answer: 1/9

Explanation:

One person can select one house out of 3= $3 C 1$ ways =3.

Hence, three persons can select one house out of 3 in 3 x 3 x 3 =9.

Therefore, probability that all thre apply for the same house is 1/9

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