Discussion
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- Question
In how many ways can the letters of the word EDUCATION be rearranged so that the relative position of the vowels and consonants remain the same as in the word EDUCATION?
Options- A. 4! x 4!
- B. 5! x 5!
- C. 4! x 5!
- D. 3! x 4!
- Correct Answer
- 4! x 5!
ExplanationThe word EDUCATION is a 9 letter word, with none of the letters repeating.
The vowels occupy 3rd,5th,7th and 8th position in the word and the remaining 5 positions are occupied by consonants
As the relative position of the vowels and consonants in any arrangement should remain the same as in the word EDUCATION, the vowels can occupy only the afore mentioned 4 places and the consonants can occupy1st,2nd,4th,6th and 9th positions.
The 4 vowels can be arranged in the 3rd,5th,7th and 8th position in 4! Ways.
Similarly, the 5 consonants can be arranged in1st,2nd,4th,6th and 9th position in5! Ways.
Hence, the total number of ways = 4! × 5! - 1. A and B together can complete a work in 3 days. They started together but after 2 days, B left the work. If the work is completed after 2 more days, B alone could do the work in how many days?
Options- A. 5
- B. 6
- C. 7
- D. 10 Discuss
- 2. A wheel makes 1000 revolutions in covering a distance of 88 km. the diameter of the wheel is?
Options- A. 24 meters
- B. 40 meters
- C. 28 meters
- D. 14 meters Discuss
- 3. 25, 36, 49, 81, 121, 169, 225
Options- A. 36
- B. 49
- C. 121
- D. 169 Discuss
- 4. (.896 x .752 +.896 x .248) / (.7 x .034 + .7 x.966) =?
Options- A. 1.28
- B. 0.976
- C. 12.8
- D. 9.76 Discuss
- 5. Einstein goes from Ahmedabad To Lucknow at the speed of 40 km/hr and returned at the speed of 60 km/hr .the average speed of Einstein during the whole journey is
Options- A. 48 km/hr
- B. 24 km/hr
- C. 50 km/hr
- D. none of these Discuss
- 6. Today is Monday. After 61 days, it will be
Options- A. Wednesday
- B. Saturday
- C. Tuesday
- D. Thursday Discuss
- 7. 9548 + 7314 = 8362 + (?)
Options- A. 8230
- B. 8410
- C. 8500
- D. 8600
- E. None of these Discuss
- 8. The true discount on a certain sum due 1 yr hence at 30% per annum, is ? 240. What is the banker' discount on the same sum for the same time and at the same rate?
Options- A. ? 400
- B. ? 212
- C. ? 312
- D. ? 445 Discuss
- 9. Calendar of month July is same as that of which month of previous year.
Options- A. May
- B. September
- C. April
- D. None of these Discuss
- 10. A coin is successively tossed two times. Find the probability of getting? (1) exactly one head (2)at least one head
Options- A. 1/2 , 3/4
- B. 2/3, 1/4
- C. 1/4, 4/5
- D. 1/2, 2/3 Discuss
More questions
Correct Answer: 6
Explanation:
(A + B)'s 2 day's work = 2 x (1/3) = 2/3
Remaining work = 1 - (2/3) = 1/3
A will complete 1/3 work in 2
A will complete 1 work in 6
A's 1 days work = 1/6
B's 1 day's work = (1/3) - (1/6) = 1/6
? B will take 6 days to complete the work alone.
Correct Answer: 28 meters
Explanation:
Distance covered in one revolution = total distance travelled / total number of revolution.
= ( 88 x 1000) / 1000 m
= 88 m
We know that the distance covered in one revolution = circumference of the wheel.
? ?d = 88
? 22d / 7 = 88
? d = 28 m
Correct Answer: 36
Explanation:
So, 36 is wrong.
Correct Answer: 1.28
Explanation:
Given expression = (.896 x .752 +.896 x .248) / (.7 x .034 + .7 x.966)
=.[896 x (.752+.248)] / [.7 x (.034+.966)]
= .(896 x 1) / ( .700 x 1)
=896/700
= 1.28
Correct Answer: 48 km/hr
Explanation:
Average speed =2 x 40 x 60 / ( 40+ 60)
= 4800 / 100
= 48 km/hr
Correct Answer: Saturday
Explanation:
Each day of the week is repeated after 7 days.
So, after 63 days, it will be Monday.
After 61 days, it will be Saturday.
Correct Answer: 8500
Explanation:
9548 16862 = 8362 + x + 7314 x = 16862 - 8362 ----- = 8500 16862 -----
Correct Answer: ? 312
Explanation:
We know that
BG = SI on TD = (240 x 30 x 1 x 1)/100
= ? 72
BG = BD - TD
? BD = BG + TD
= 72 + 240
= ? 312
Correct Answer: May
Explanation:
If previous year is leap year then calendar of May is similar to July
Correct Answer: 1/2 , 3/4
Explanation:
In tossing a coin 2 times the sample space is 4 i,e (H, H), (H, T), (T, H), (T, T)
(1) If A1 denotes exactly one head
then A1 = {(H, T) (T, H) }
So, P(A1 ) = 2/4 = 1/2
(2) If A denotes at least one head
then A = {(H, T) (T, H) (H, H)}
? A = {(H, T) (T, H) (H, H )}
? P(A) = 3/4
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