Difficulty: Medium
Correct Answer: 2520
Explanation:
Introduction / Context:
This question asks for the number of permutations of the letters of the word ABYSMAL. Here, one letter is repeated, which means we must adjust the basic factorial formula for permutations of distinct items to account for indistinguishable letters.
Given Data / Assumptions:
Concept / Approach:
If there are n total letters, with one letter repeated r times and the rest distinct, then the number of distinct permutations is n! / r!. This divides out the overcount due to the indistinguishability of the repeated letters. Here we have 7 letters in total with A repeated 2 times, so we use 7! / 2!.
Step-by-Step Solution:
Step 1: Count total letters in ABYSMAL. There are 7 letters.Step 2: Count how many times each letter appears. A appears 2 times; B, Y, S, M, L appear 1 time each.Step 3: Use the formula for permutations with one repeated letter: total permutations = 7! / 2!.Step 4: Compute 7! = 5040.Step 5: Compute 2! = 2.Step 6: Divide: 5040 / 2 = 2520.
Verification / Alternative check:
Why Other Options Are Wrong:
Common Pitfalls:
A common mistake is to forget that the two As are identical and simply use 7!, which is wrong. Some students also incorrectly divide by more than 2!, imagining extra repetitions that do not exist. Carefully counting how many times each letter appears and then applying the n! divided by product of factorials of repeated counts is essential.
Final Answer:
The total number of different arrangements of the letters of ABYSMAL is 2520.
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