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- Question
In a mixture of milk and water the proportion of water by weight was 75%. If in 60 gm of mixture 15 gm water was added, what would be the percentage of water ? (Weight in gm)
Options- A. 80%
- B. 70%
- C. 75%
- D. 62%
- Correct Answer
- 80%
ExplanationWater in 60 gm mixture=60 x 75/100 = 45 gm. and Milk = 15 gm.
After adding 15 gm. of water in mixture, total water = 45 + 15 = 60 gm and weight of a mixture = 60 + 15 = 75 gm.
So % of water = 100 x 60/75 = 80%.
- 1. A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold?
Options- A. 58 l
- B. 65 l
- C. 50 l
- D. 62 l Discuss
- 2. From a container of wine, a thief has stolen 15 litres of wine and replaced it with same quantity of water. He again repeated the same process. Thus, in three attempts the ratio of wine and water became 343 : 169. The initial amount of wine in the container was:
Options- A. 75 litres
- B. 100 litres
- C. 150 litres
- D. 120 litres Discuss
- 3. A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained ?
Options- A. 5:3
- B. 1:4
- C. 4:1
- D. 9:1 Discuss
- 4. From a container of wine, a thief has stolen 15 liters of wine and replaced it with same quantity of water.He again repeated the same process. Thus in three attempts the ratio of wine and water became 343:169. The initial amount of wine in the container was:
Options- A. 75 liters
- B. 100 liters
- C. 150 liters
- D. 120 liters Discuss
- 5. Ratio of water and milk in a container is 2 : 3. If 40 liter mixture removed from the container and same quantity of milk is added to it then the ratio of water to milk becomes 1 : 4. Find the initial quantity of mixture ?
Options- A. 75 lit
- B. 80 lit
- C. 85 lit
- D. 90 lit Discuss
- 6. In a 48 ltr mixture, the ratio of milk and water is 5:3. How much water should be added in the mixture so as the ratio will become 3:5 ?
Options- A. 24 lit
- B. 16 lit
- C. 32 lit
- D. 8 lit Discuss
- 7. A jar was full with honey. A person used to draw out 20% of the honey from the jar and replaced it with sugar solution. He has repeated the same process 4 times and thus there was only 512 gm of honey left in the jar, the rest part of the jar was filled with the sugar solution. The initial amount of honey in the jar was filled with the sugar solution. The initial amount of honey in the jar was:
Options- A. 1.25 kg
- B. 1 kg
- C. 1.5 kg
- D. None of these Discuss
- 8. A man pays Rs. 6.40 per litre of milk. He adds water and sells the mixture at Rs. 8 per litre, thereby making 37.5% profit. The proportion of water to milk received by the customers is
Options- A. 1 : 10
- B. 10 : 1
- C. 9 : 11
- D. 11 : 9 Discuss
- 9. A mixture contains 25% milk and rest water. What percent of this mixture must taken out and replaced with milk so that in mixture milk and water may become equal.
Options- A. 31.8%
- B. 31%
- C. 33.33%
- D. 29.85% Discuss
- 10. A container contains 50 litres of milk. From that 8 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container ?
Options- A. 24.52 litres
- B. 29.63 litres
- C. 28.21 litres
- D. 25.14 litres Discuss
Alligation or Mixture problems
Search Results
Correct Answer: 50 l
Explanation:
Let the tin contain 5x litres of liquids
=> 5(4x - 36) = 2(x + 36)
=> 20x - 180 = 2x + 72
=> x = 14 litres
Hence, the initial quantity of mixture = 70l
Quantity of liquid B
=
= 50 litres.
Correct Answer: 120 litres
Explanation:
It means (since 343 + 169 = 512)
Thus,
Thus the initial amount of wine was 120 liters.
Correct Answer: 9:1
Explanation:
Milk = 3/5 x 20 = 12 liters, water = 8 liters
If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.
Remaining milk = 12 - 6 = 6 liters
Remaining water = 8 - 4 = 4 liters
10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters.
The ratio of milk and water in the new mixture = 16:4 = 4:1
If the process is repeated one more time and 10 liters of the mixture are removed,
then amount of milk removed = 4/5 x 10 = 8 liters.
Amount of water removed = 2 liters.
Remaining milk = (16 - 8) = 8 liters.
Remaining water = (4 -2) = 2 liters.
Now 10 lts milk is added => total milk = 18 lts
The required ratio of milk and water in the final mixture obtained
= (8 + 10):2 = 18:2 = 9:1.
Correct Answer: 120 liters
Explanation:
It means
Thus ,
=> K = 120
Thus the initial amount of wine was 120 liters.
Correct Answer: 80 lit
Explanation:
From the given data,
let the initial quantity of the mixture = 5x
Then,
Then the initial quantity of the mixture = 5x = 5 x 16 = 80 lit.
Correct Answer: 32 lit
Explanation:
Given mixture = 48 lit
Milk in it = 48 x 5/8 = 30 lit
=> Water in it = 48 - 30 = 18 lit
Let 'L' lit of water is added to make the ratio as 3:5
=> 30/(18+L) = 3/5
=> 150 = 54 + 3L
=> L = 32 lit.
Correct Answer: 1.25 kg
Explanation:
Let the initial amount of honey in the jar was K, then
or
Therefore, K = 1250
Hence initially the honey in the jar= 1.25 kg
Correct Answer: 1 : 10
Explanation:
Customer ratio of Milk and Water is given by
Milk :: Water
6.4 0
=> Milk : Water = 110 : 11 = 10 : 1
Therefore, the proportionate of Water to Milk for Customer is 1 : 10
Correct Answer: 33.33%
Explanation:
Now, take percentage of milk and applying mixture rule
25 100
50
50 25 = 2 : 1
Hence required answer = 1/3 or 33.33%
Correct Answer: 29.63 litres
Explanation:
Given that container has 50 litres of milk.
After replacing 8 litres of milk with water for three times, milk contained in the container is:
= 29.63 litres.
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