K ? L > M ? N
Conclusions
I. N ? K (x)
II. N < K (?)
Thus, only Conclusion II follows.
Conclusion
I. C > N (?)
II. B > N (?)
Conclusions
As per given question, we can draw the below conclusion,
I. D > N (?)
II. C ? K (X)
Solve all option one by one,
36 + 6 - 3 x 2 = 20
After changing the symbol as per question,
36 ÷ 6 x 3 + 2 = 20
Apply the BODMAS rule,
? 6 x 3 + 2 = 20
? 18 + 2 = 20
? 20 = 20
Given question is,
40 x 12 + 3 - 6 ÷ 60
According to the question, putting the real values of signs,
40 + 12 ÷ 3 x 6 - 60 = 40 + 4 x 6 - 60
Apply the BODMAS Rule
= 40 + 24 - 60 = 64 - 60 = 4
Solve the equation by using option one by one.
5 * 6 * 5 * 8 * 14
From option (b),
After changing the symbol as per question,
5 x 6 ÷ 5 + 8 = 14
Apply the BODMAS Rule,
? 5 x 6/5 + 8 = 14
? 14 = 14
Z ? Y = W ? X
Conclusions
I. W < Z (?)
or
II. W = Z (?)
Thus, either Conclusion I or II follows.
Statements
R # J ? R >J
J $ D ? J ? D
D @ K ? D = K
K % T ? K ? T
i.e., R > J ? D = K ? T
Conclusions
I. T # D ? T > D (may be)
II. T @ D ? T = D (may be)
III. R # K ? R > K (?)
IV. J $ T ? J ? T (x)
Hence, either conclusion I or II and III are definitely true.
Statements
T % R ? T ? R
R $ M ? R ? M
M @ D ? M = D
D © H ? D < H
i.e., T ? R ? M = D < H
Conclusions
I. D % R ? D ? R (?)
II. H # R ? H > R (x)
III. T ©M ? T < M (x)
IV. T % D ? T ? D (x)
Hence conclusion I is definitely true.
Statements
M @ B ? M = B
B # N ? B > N
N $ R ? N ? R
R © K ? R < K
i.e., M = B > N ? R < K
Conclusions
I. K # B ? K > B (x)
II. R © B ? R < B (?)
III. M $ R ? M ? R (x)
IV. N © M ? N < M (?)
Hence, II and IV are definitely true.
Statements
F # H ? F > H
H @ M ? H = M
M © E ? M < E
E $ J ? E ? J
i.e., F > H = M < E ? J
Conclusions
I. J © M ? J < M (x)
II. E # H ? E > H (?)
III. M © F ? M < F (?)
IV. F # E ? F > E (x)
Hence, II and III are definitely true.
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