Correct Answer:
Explanation:
Statements ::
D % A ⇒ D ≤ A
A @ B ⇒ A = B
B © K ⇒ B < K
K % M ⇒ K ≤ M
i.e., D ≤ A = B < K ≤ M
Conclusions
I. B $ D ⇒ B ≥ D (✔)
II. K # A ⇒ K > A (✔)
III. M # B ⇒ M > B (✔)
IV. A © M ⇒ A < M (✔)
Hence, all Conclusion I, II, III and IV are definitely true.
Discussion & Comments